Answer: The atomic mass in the periodic table is a weighted average of all naturally occuring isotopes of zinc.
Explanation: The elements consist of protons, neutrons, and electrons. Protons and nuetrons are assigned a mass of 1 amu (atomic mass unit). Electrons are too small to make a big difference in the mass, so they are assign a 0 for their amu. Since the elements consist of just these three particles, any one atom must add up to a whole number atomic mass. Zinc consists of 30 protons, by definition. A neutral atom has 30 electrons. The balance of a zinc atom is made up of neutrons. A Zn-65 atom would have 30 protons and 35 neutrons:
30 Protons = 30 amu
35 Neutrons = 35 amu
30 Electrons = 0 amu
Total AMU = 65
Any <em><u>ONE </u></em> Zn atom should have a whole number atomic mass. But zinc in the environment has isotopes of zinc - atoms that contain differing numbers of neutrons. A Zn-66 atom would have 36, instead of 35 neutrons. (P:30, N:36, E:0 = 66 amu). The atomic mass in the Periodic Table reflects the average of these isotopes as found in the environment. If the 65 and 66 isotopes were the only ones found naturally, an atomic mass of 65.38 would suggest around 60% of the atoms are Zn-65 and 40% are Zn-66. The average weight atomic mass would would be 65.40
This problem is providing the ratio of nitrogen to oxygen by mass in nitrogen monoxide, NO, as 7.0:8.0 and asks for the same ratio but in NO₂ and N₂O₇. After doing the calculations, the results are 7.0:16.0 and 1.0:4.0 respectively.
<h3>Mass ratios:</h3>
In chemistry, one can calculate the mass ratios in chemical formulas according to the atomic mass of each atom. In such a way, one knows the mass ratio of nitrogen to oxygen in NO is 7.0:8.0 because we divide the atomic mass of nitrogen by oxygens:
![\frac{14}{16}=\frac{7.0}{8.0}](https://tex.z-dn.net/?f=%5Cfrac%7B14%7D%7B16%7D%3D%5Cfrac%7B7.0%7D%7B8.0%7D%20%20)
Now, for chemical formulas with subscripts, one must multiply the atomic mass of the element by the subscript in the formula, which is the case of NO₂ and N₂O₇ as shown below:
![NO_2:\frac{14}{16*2}=\frac{14}{32} =\frac{7.0}{16.0} \\ \\ N_2O_7:\frac{14*2}{16*7}=\frac{28}{112} =\frac{1.0}{4.0}](https://tex.z-dn.net/?f=NO_2%3A%5Cfrac%7B14%7D%7B16%2A2%7D%3D%5Cfrac%7B14%7D%7B32%7D%20%3D%5Cfrac%7B7.0%7D%7B16.0%7D%20%20%5C%5C%0A%5C%5C%0AN_2O_7%3A%5Cfrac%7B14%2A2%7D%7B16%2A7%7D%3D%5Cfrac%7B28%7D%7B112%7D%20%3D%5Cfrac%7B1.0%7D%7B4.0%7D%20)
Therefore, the results for NO₂ and N₂O₇ are 7.0:16.0 and 1.0:4.0 respectively
Learn more about atomic masses: brainly.com/question/5566317
Answer:
Hydrogen(H2), Nitrogen(N2), Oxygen(O2), Chlorine(Cl2), Bromine(B2), and Iodine(I2), all have two atoms each in their molecules. So, the atomicity of hydrogen, nitrogen, oxygen, chlorine, bromine and iodine is 2 each.
Explanation:
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Tea is a homogeneous mixture as its composition is the same throughout. If you take one spoon of the solution and compare it to two spoons of the same solution, the composition will be the same. Also, the different components which make up a cup of tea cannot be observed individually. All the components mix up thoroughly.