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sergey [27]
3 years ago
15

Compounds have the same properties as the elements they are made up of. Is it true or false

Chemistry
1 answer:
hodyreva [135]3 years ago
6 0
( False ) this the answer
You might be interested in
BASIC CALCULATIONS IN SPECTROSCOPY
gayaneshka [121]

Answer: 25%

Explanation:  

1. Transmittance, T= P/P0  

Where P = light exiting the cell

           P0 = light entering the cell

Therefore %T =  P/P0 ×100

           = 50/200×100

=25%

2. Absorbance, A= -log(T)

But T= 0.25

Therefore A= -log(0.25)

                  = 0.6020

7 0
3 years ago
Ca(s) + O₂(g) + S(s) → CaSO4(s)
san4es73 [151]

The mass of Calcium required to complete this reaction is 4.008 g.

  • Law of conservation of mass states that In a closed system, mass cannot be produced or destroyed, but it can be changed from one form to another.
  • The mass of the chemical constituents before a chemical reaction is equal to the mass of the constituents after the reaction.
  • In several disciplines, including chemistry, mechanics, and fluid dynamics, the idea of mass conservation is widely applied.

In the given reaction mass of product after completion of reaction is 13.614 g that means total mass of constituents before reaction should also be 13.614.

So,

mass of Ca + mass of O₂ + mass of S = mass of CaSO4

Ca + 6.400 g + 3.206 g = 13.614 g

mass of Ca = 13.614 - 9.606 = 4.008 g

Therefore, by law of conservation of mass 4.008 g of Ca is required for the completion of the reaction.

Learn more about mass conservation here:

brainly.com/question/2030891

#SPJ9

5 0
2 years ago
What is the process of neutralization reactions?
stich3 [128]
ACID + BASE = SALT + WATER 
6 0
3 years ago
a solution is made by dissolving 14.57 g of sodium bromide nabr in 415 of water . what is the molality of the solution?
jenyasd209 [6]

Answer:

The answer to your question is molality = 0.34

Explanation:

Data

mass of NaBr = 14.57 g

mass of water = 415 g.

molality = ?

Process

1.- Calculate the molar mass of NaBr

NaBr = 23 + 80 = 103 g

2.- Calculate the moles of NaBr

                     103 g of NaBr ------------------ 1 mol

                      14.57 g of NaBr ---------------  x

                               x = (14.57 x 1) / 103

                               x = 14.57 / 103

                               x = 0.141 moles

3.- Calculate the molality

molality = moles / volume

-Substitution

molality = 0.141 / .415

-Result

molality = 0.34

4 0
3 years ago
Read 2 more answers
In a chemical reaction, where is the catalyst located
ASHA 777 [7]

Answer:

A. on the reactant side

Explanation:

A catalyst will appear in the steps of a <u>reaction mechanism</u>, but it will not appear in the overall chemical reaction

6 0
3 years ago
Read 2 more answers
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