Mole ratio is the coefficients 4:3
<span>4Fe + 3O2</span>
Hey there!:
Balanced equation:
F2(g) + CaBr2(s) ---> CaF2 + Br2
1 mol F2 = 1 mol CaBr2
Calculation:
2.31 g CaBr2
* (1 mol CaBr2 / 199.886 g CaBr2) * (1 mol F2 / 1 mol CaBr2)
= 0.0115565 moles of F2:
Assuming F2 is an ideal
gas at these conditions:
P*V = n*R*T
Solving for V:
V = (n *R* T) / P
where :
n = 0.0115565 moles
R = 0.08206 atm·L/mol·K
Temperature in K = 35 + 273.15 => 308.15 K
P = 8.19 atm
Substituting numbers into V = (n x R x T) / P:
V = 0.0115565 * 0.08206 * 308.15 / 8.19
V = 0.29222 / 8.19
V = 0.0357 or 3.57*10⁻² L
You are correct!!!
Hope that helps!
C=3.0 mol/L
n=1.50 mol
n=cv
v=n/c
v=1.50/3.0=0.5 L = 500 mL
Answer: The concentration of 
is 0.08 M.
Explanation:-
According to the neutralization law,
where,
= molarity of 
solution = 0.105 M
= volume of solution = 25 ml
= molarity of solution = ?
= volume of solution = 31.5 ml
= valency of = 1
= valency of = 1
Therefore, the concentration of is 0.08 M.
Yes, it is correct...........
