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3 years ago

Samira is playing a game with the spinner shown.

Mathematics

1 answer:

liraira [26]3 years ago

7 0

Answer:

2/10 or 1/5

Step-by-step explanation:

there are 10 equal 'slices'

then count those with a J

that would be 2

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A card is drawn at random from a standard deck of 52 cards. Find the following conditional probabilities. a) The card is a diam

Inga [223]

Answer:

$a.\frac{1}{13}\\b.\frac{1}{2}\\c.\frac{1}{13}\\d.\frac{1}{13}$

Step-by-step explanation:

P(A|B) = P(A and B) / P(B)

Total number of cards = 52

Let A denotes the event that the card is a diamond and B denotes the card is red.

$P\left ( A|B \right )=\frac{P\left ( A\cap B \right )}{P(B)}\\=\frac{\frac{2}{52}}{\frac{26}{52}}\\=\frac{1}{13}$

Let A denotes the event that the card is red and B denotes the card is diamond.

$P\left ( A|B \right )=\frac{P\left ( A\cap B \right )}{P(B)}=\frac{\frac{2}{52}}{\frac{4}{52}}\\=\frac{1}{2}$

Let A denotes the event that the card is nine and B denotes the card is red.

$P\left ( A|B \right )=\frac{P\left ( A\cap B \right )}{P(B)}=\frac{\frac{2}{52}}{\frac{26}{52}}\\=\frac{1}{13}$

Let A denotes the event that the card is a king and B denotes the card is a face card.

$P\left ( A|B \right )=\frac{P\left ( A\cap B \right )}{P(B)}=\frac{\frac{4}{52}}{\frac{12}{52}}\\=\frac{1}{13}$

7 0

2 years ago

Which rational number equals 0 point 4 with bar over 4?

Ulleksa [173]

<h3>Answer: 4/9</h3>

==============================================

Work Shown:

$x = 0.\overline{4}\\\\x = 0.4444\ldots\\\\10x = 4.4444\ldots\\\\10x-x = 4.4444\ldots-0.4444\ldots\\\\9x = 4\\\\x = \frac{4}{9}\\\\\frac{4}{9} = 0.\overline{4}= 0.4444\ldots\\\\$

The idea is that when we subtract 10x and x, the infinite decimal pattern (the 4s that go on forever) will cancel. That leads to 9x = 4 which solves to x = 4/9

6 0

3 years ago

HELP!!!!! PLEASE!!!!!

emmainna [20.7K]

Answer:

Step-by-step explanation:

It's a pythagorean triple

8 0

2 years ago

Read 2 more answers

Find value the value of x in the image below please help

Marianna [84]