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3 years ago

What is the surface area of the sphere?

Mathematics

1 answer:

Fantom [35]3 years ago

7 0

Answer:

<em>The surface area of the sphere is 314 mi².</em>

Step-by-step explanation:

According to the given diagram, the diameter of the sphere is 10 mi.

If the radius is $r$ , then diameter $=2r$

So....

$2r=10\\ \\ r=\frac{10}{2}= 5$

<u>Formula for the surface area of a sphere</u>: $A_{S}= 4\pi r^2$

Plugging the value of $r$ into this formula, we will get...

$A_{S}=4\pi(5)^2\\ \\ A_{S}=4\pi(25)\\ \\ A_{S}=4(3.14)(25)\ \ [Using\ \pi=3.14]\\ \\ A_{S}=314$

So, the surface area of the sphere is 314 mi².

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How do you convert 7/6 into a mixed number

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Wel its kinda difficult to say but look on how much times 6 can fit into 7 which is 1 but that will be 6,so in order to become seven you need 1 which is our left over number,so in the end you will get 1 whole and 1/6 and you use the leftover number as your numerator and just leave the 6 as it was.Whoof that was long but its no nearly as long as i explain it.

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3 years ago

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I need help for question 17 in my big ideas math homework, it says "Use the figure to find the measures of the numbered angles."

Dafna1 [17]

Answer:

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Step-by-step explanation:

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2 years ago

Identify the figure that portrays the translation of the given preimage as indicated by the direction arrow. Preimage: (1st one

Westkost [7]

Answer:

The triangle will translate along the arrow and reach the head of the arrow.

Step-by-step explanation:

Translation is a category of motion in which one body moves along towards a particular direction and reaches a particular point.

In translation, the rotational motion is not present. Also, the translational motion is a one dimensional motion.

In the given figure, the triangle is present at the tail of the arrow.

The arrow depicts the direction of the translational motion.

So, the triangle will reach the end of the arrow as shown in the picture present in the attachment.

For more explanation, refer the following link:

brainly.com/question/17540330

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2 years ago

Please help with any of this Im stuck and having trouble with pre calc is it basic triogmetric identities using quotient and rec

german

How I was taught all of these problems is in terms of r, x, and y. Where sin = y/r, cos = x/r, tan = y/x, csc = r/y, sec = r/x, cot = x/y. That is how I will designate all of the specific pieces in each problem.

Let's start with sin here. $\frac{2\sqrt{5}}{5} = \frac{2}{\sqrt{5}}$ Therefore, because sin is y/r, r = $\sqrt{5}$ and y = +2. Moving over to cot, which is x/y, x = -1, and y = 2. We know y has to be positive because it is positive in our given value of sin. Now, to find cos, we have to do x/r.

cos = $\frac{-1}{\sqrt{5}} = \frac{-\sqrt{5}}{5}$

Let's start with secant here. Secant is r/x, where r (the length value/hypotenuse) cannot be negative. So, r = 9 and x = -7. Moving over to tan, x must still equal -7, and y = $4\sqrt{2}$ . Now, to find csc, we have to do r/y.

csc = $\frac{9}{4\sqrt{2}} = \frac{9\sqrt{2}}{8}$

The pythagorean identities are

sin^2 + cos^2 = 1,

1 + cot^2 = csc^2,

tan^2 + 1 = sec^2.

Let's take a look at the information given here. We know that cos = -3/4, and sin (the y value), must be greater than 0. To find sin, we can use the first pythagorean identity.

sin^2 + (-3/4)^2 = 1

sin^2 + 9/16 = 1

sin^2 = 7/16

sin = $\sqrt{7/16}$ = $\frac{\sqrt{7}}{4}$

Now to find tan using a pythagorean identity, we'll first need to find sec. sec is the inverse/reciprocal of cos, so therefore sec = -4/3. Now, we can use the third trigonometric identity to find tan, just as we did for sin. And, since we know that our y value is positive, and our x value is negative, tan will be negative.

tan^2 + 1 = (-4/3)^2

tan^2 + 1 = 16/9

tan^2 = 7/9

tan = - $\sqrt{7/9} = \frac{-\sqrt{7}}{3}$

Let's take a look at the information given here. If we know that csc is negative, then our y value must also be negative (r will never be negative). So, if cot must be positive, then our x value must also be negative (a negative divided by a negative makes a positive). Let's use the second pythagorean identity to solve for cot.

1 + cot^2 = $(\frac{-\sqrt{6}}{2})^{2}$

1 + cot^2 = 6/4

cot^2 = 2/4

cot = $\frac{\sqrt{2}}{2}$

tan = $\sqrt{2}$

Next, we can use the third trigonometric identity to solve for sec. Remember that we can get tan from cot, and cos from sec. And, from what we determined in the beginning, sec/cos will be negative.

$(\frac{2}{\sqrt{2}})^2$ + 1 = sec^2