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3 years ago

Describe the separation technique that could be used to separate two colorless liquids with varying boiling points.

Chemistry

1 answer:

Over [174]3 years ago

3 0

Distillation; either simple or fractional macroscale depending on how far apart the boiling points are.

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2CO + O2 --> 2CO2

GREYUIT [131]

Answer:

10 L of CO₂.

Explanation:

The balanced equation for the reaction is given below:

2CO + O₂ —> 2CO₂

From the balanced equation above,

2 L of CO reacted to produce 2 L of CO₂.

Finally, we shall determine the volume of CO₂ produced by the reaction of 10 L CO. This can be obtained as follow:

From the balanced equation above,

2 L of CO reacted to produce 2 L of CO₂.

Therefore, 10 L of CO will also react to produce 10 L of CO₂.

Thus, 10 L of CO₂ were obtained from the reaction.

3 0

3 years ago

For the following problems, identify the substance as either an element, a compound, or a mixture. Write E for Element, C for co

andre [41]

Answer:

Explanation:

34. E

35. M

36. C

37. M

38. E

39. C

3 0

3 years ago

- Which of the following is an example of physical change?

dalvyx [7]

B as the glass just changes form as it shattered but the chemical composition is same as it was before

5 0

3 years ago

What characteristic is descriptive of a solution?

Snezhnost [94]

A solution is a mixture of two or more substances combined so that it is uniform, which means you cannot see the components. <span />

8 0

3 years ago

What is the specific heat of a substance that absorbs 2500 joules of heat when a sample of 100g of the substance increases in te

Ierofanga [76]

Answer:

0.417 J/gºC

Explanation:

From the question given above, the following data were obtained:

Heat (Q) absorbed = 2500 J

Mass (M) of substance = 100 g

Initial temperature (T1) = 10 °C

Final temperature (T2) = 70 °C

Specific heat capacity (C) =?

Next, we shall determine the change in temperature (ΔT). This can be obtained as follow:

Initial temperature (T1) = 10 °C

Final temperature (T2) = 70 °C

Change in temperature (ΔT) =?

Change in temperature (ΔT) = T2 – T1

Change in temperature (ΔT) = 70 – 10

Change in temperature (ΔT) = 60 °C

Finally, we shall determine the specific heat capacity of the substance as follow:

Heat (Q) absorbed = 2500 J

Mass (M) of substance = 100 g

Change in temperature (ΔT) = 60 °C

Specific heat capacity (C) =?

Q = MCΔT

2500 = 100 × C × 60

2500 = 6000 × C

Divide both side by 6000

C = 2500 / 6000

C = 0.417 J/gºC

Therefore, the specific heat capacity of substance is 0.417 J/gºC

5 0

2 years ago