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4 years ago

Describe the separation technique that could be used to separate two colorless liquids with varying boiling points.

Chemistry

1 answer:

Over [174]4 years ago

3 0

Distillation; either simple or fractional macroscale depending on how far apart the boiling points are.

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Min is conducting an experiment where he compares the properties of water and lemonade. The first stage of the experiment is foc

vampirchik [111]

Answer: i need help

Explanation:

6 0

4 years ago

Consider Al at room temperature. Its electron density is n = 18 x 1022 cm-3 and its electrical resistivity is rho = 2.45 μΩ-cm.

Marianna [84]

Answer:

$\tau=1.28968\times 10^{-8}\ s$ is the electron relaxation time

$l=9.6726\times 10^{-4}\ m$ is the mean free path

Explanation:

Given:

electron density of aluminium at room temperature, $n=18\times 10^{22}\ cm^{-3}$

resistivity of aluminium, $\rho=2.45\times 10^{-8}\ \Omega.m$

From the Drude's model we have:

$\tau=\frac{m}{\rho.n.q^2}$

where:

$\tau=$ electron relaxation time

$m=$ mass of a charge

$q=$ magnitude of a charge

Putting respective values for electron:

$\tau=\frac{9.1\times 10^{-31}}{2.45\times 10^{-8}\times 18\times 10^{22}\times (1.6\times 10^{-19})^2}$

$\tau=8.0605\times 10^{-9}\ s$

Mean free path is given as:

$l=v_a.\tau$

where:

$l=$ mean free path

$v_a=$ average velocity of electrons

Now we have the the general value of average velocity of electrons at room temperature:

$v_a=120000\ m.s^{-1}$

So,

$l=120000\times 8.0605\times 10^{-9}$

$l=9.6726\times 10^{-4}\ m$

8 0

3 years ago

How will fragmentation affect the mass spectrum of hydrogen chloride?

Mnenie [13.5K]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
if fragments of HCl occur then two peaks will be observed 1st at 1 (for H) 2nd at 35.5 (for Cl) but there will not be molecular peak of HCl because in fragmentation the molecule breaks due to which no molecular peak is obtained.

7 0

4 years ago

Hydrogen and iodine react to form hydrogen iodide, like this: H_2 (g) + I_2 (g) rightarrow 2 HI(g) Also, a chemist finds that at

telo118 [61]

This is an incomplete question, here is a complete question.

Hydrogen and iodine react to form hydrogen iodide, like this:

$H_2(g)+I_2(g)\rightarrow 2HI(g)$