A) 125 * 10 = 1250 chinchillas in a year;
1250 * 2 = 2500 chinchillas in two years;
b) y = x + 433, where 433 = 933 - 500;
c) 933 + 433 = 1366 chinchillas they have <span>at the end of two years;</span>
(2x-5y) + (x+y)
= (2x+x) + (-5y+y)
= 3x + (-4y)
= 3x-4y
So option A is the correct one.
Answer:
Step-by-step explanation:
<u>Given:</u>
- G = (11,-5)
- M = (4,-4)
- R = ?
<u>Solution</u>
<u>As per midpoint formula;</u>
- 4 = (11 + x)/2 ⇒ x + 11 = 8 ⇒ x = 3
- -4 = (-5 + y)/2 ⇒ y - 5 = -8 ⇒ y = -3
- R = (3, -3)
Answer: -9°F
Step-by-step explanation:
From the question, we are told that the temperature at 6:00 am was -12 Fahrenheit and that the temperature increased by 1/2 Fahrenheit each hour for 6 hours.
The temperature, in degrees Fahrenheit, at noon would be:
= -12°F + 1/2(6)
= -12°F + 3°F
= -9°F
Answer:
It would've been more difficult to solve and doing it as shown in EX:2 it's a way easier method to use and remember.
