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Norma-Jean [14]
3 years ago
14

a bubble of air of volume 1cm^3 is released by a deep sea diver at a depth where the pressure is 4.0 atmospheres. assuming its t

emperature remains constant (T1=T2), what is its volume just before it reaches the surface where the pressure is 1.0 atmosphere?
Physics
1 answer:
lys-0071 [83]3 years ago
8 0

Answer:

hope this helps!

Explanation:

Volume of the air bubble, V1=1.0cm3=1.0×10−6m3

Bubble rises to height, d=40m

Temperature at a depth of 40 m, T1=12oC=285K

Temperature at the surface of the lake, T2=35oC=308K

The pressure on the surface of the lake: P2=1atm=1×1.103×105Pa 

The pressure at the depth of 40 m: P1=1atm+dρg

Where,

ρ is the density of water =103kg/m3

g is the acceleration due to gravity =9.8m/s2

∴P1=1.103×105+40×103×9.8=493300Pa

We have T1P1V1=T2P2V2

Where, V2 is the volume of the air bubble when it reaches the surface.

V2=

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Estimate how far apart the rays of deepest red and deepest violet light are as they exit the bottom surface. assume nred = 1.57
Harlamova29_29 [7]
We begin by noting that the angle of incidence is the one that's taken with respect to the normal to the surface in question. In this case the angle of incidence is 30. The material is Flint Glass according to the original question. The refractive indez of air n1=1, the refractive index of red in flint glass is nred=1.57, finally for violet in the glass medium is nviolet=1.60. Snell's Law dictates:
n_1sin(\theta_1)=n_2sin(\theta_2)
Where \theta_2 differs for each wavelenght, that means violet and red will have different refractive indices in the glass.
In the second figure provided details are given on which are the angles in question, \Delta x is the distance between both rays.
\theta_{2red}=Asin(\frac{sin(30)}{1.57})\approx 18.5705
\theta_{2violet}=Asin(\frac{sin(30)}{1.60})\approx 18.21
At what distance d from the incidence normal will the beams land at the bottom?
For violet we have:
d_{violet}=h.tan(\theta_{2violet})\approx 0.0132m
For red we have:
d_{red}=h.tan(\theta_{2red})\approx 0.0134m
We finally have:
\Delta x=d_{red}-d_{violet}\approx2.8\times10^{-4}m


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PSYCHOLOGY! A _________ is a graphical representation of association between variables.
pshichka [43]

Answer:

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The total blood volume of a human is 75 ml/kg. If the volumetric flow rate is the same in adults and children, how much more blo
Tema [17]

The amount of blood that flows through the venae cavea of the adult is 3750 ml more than that of the child.

<h3>What is flow rate?:</h3>

This is the volume of fluid flowing in a vessel per unit time.

First, we need to get the volume of blood flowing through the venae cavae of the adult and the child in 1 hour, then subtract the volume of blood for the child from that of the adult.

Using,

  • V = F'm................ Equation 1

Where:

  • V = Volume of the blood
  • F' = Flow rate
  • m = mass of blood.

For the Adult,

Given:

  • m = 70 kg
  • F = 75 ml/kg

Substitute these values into equation 1

  • V = 70(75)
  • V = 5250 ml.

For the child,

Given:

  • m = 20 kg
  • F = 75 ml/kg

Substitute these values into equation 1 also

  • V = 75(20)
  • V = 1500 ml.

The amount of blood that flows more through the adult than the child is

  • A = 5250-1500
  • A = 3750 ml.

Hence, the amount of blood that flows through the venae cavea of the adult is 3750 ml more than that of the child.

Learn more about flow rate here: brainly.com/question/21630019

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