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CaHeK987 [17]
3 years ago
12

Which applies the power of a power rule properly to simplify the expression (710)5?

Mathematics
1 answer:
natulia [17]3 years ago
8 0

Answer:

I45

Step-by-step explanation:

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The table below shows some input and output values for a function named F(n). Which of the following equations describes F(n)?
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It looks like it would be C, but I'm not sure 
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a deli sells a sandwich spread for 6.40 per pound. how much do you have to pay for 24 ounces of the spread
rjkz [21]
In the given question the most important part is convert ounce to pound and then the problem becomes easy. We already know
1 ounce = 0.0625 pounds
Then
24 ounce = 0.0625 * 24 pounds
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Now let us focus on the problem in hand and the information's that are already given in the question.
The cost per pound of the sandwich sold by Deli = 6.40
Then
The cost of 1.5 pound of sandwich sold by Deli = 6.40 * 1.5
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So the cost of 24 ounces of spread is 9.60.
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Evaluate the six trigonometric functions of the angle 0<br><br><br><br>is right<br>​
antiseptic1488 [7]

Answer:

1. Sine θ = 1/3

2. Cos θ = 2√2 / 3

3. Tan θ = √2 / 4

4. Cosec θ = 3

5. Sec θ = 3√2 / 4

6. Cot θ = 2√2

Step-by-step explanation:

We'll begin by determining the adjacent. This can be obtained as follow:

Hypothenus (Hypo) = 9

Opposite (Opp) = 3

Adjacent (Adj) =?

Hypo² = Adj² + Opp²

9² = Adj² + 3²

81 = Adj² + 9

81 – 9 = Adj²

72 = Adj²

Take the square root of both side

Adj = √72

Adj = 6√2

Finally, we shall determine six trigonometric functions of the angle θ. This Can be obtained as follow:

1. Determination of Sine θ

Hypothenus = 9

Opposite = 3

Sine θ =?

Sine θ = Opposite / Hypothenus

Sine θ = 3/9

Sine θ = 1/3

2. Determination of Cos θ

Adjacent = 6√2

Hypothenus = 9

Cos θ =?

Cos θ = Adjacent / Hypothenus

Cos θ = 6√2 / 9

Cos θ = 2√2 / 3

3. Determination of Tan θ

Opposite = 3

Adjacent = 6√2

Tan θ =?

Tan θ = Opposite / Adjacent

Tan θ = 3 / 6√2

Tan θ = 1 / 2√2

Rationalise

(1 / 2√2) × (2√2 /2√2)

= 2√2 / 4×2

Tan θ = √2 / 4

4. Determination of Cosec θ

Sine θ = 1/3

Cosec θ =?

Cosec θ = 1 / Sine θ

Cosec θ = 1 ÷ 1/3

Cosec θ = 1 × 3/1

Cosec θ = 3

5. Determination of sec θ

Cos θ = 2√2 / 3

Sec θ =?

Sec θ = 1 / Cos θ

Sec θ = 1 ÷ 2√2 / 3

Sec θ = 1 × 3 / 2√2

Sec θ = 3 / 2√2

Rationalise

= (3 / 2√2) × (2√2 / 2√2)

= 3 × 2√2 / 4×2

Sec θ = 3√2 / 4

6. Determination of Cot θ

Tan θ = √2 / 4

Cot θ =?

Cot θ = 1 / Tan θ

Cot θ = 1 ÷ √2 / 4

Cot θ = 1 × 4 / √2

Cot θ = 4 / √2

Rationalise

= (4 / √2) × (√2 / √2)

= 4√2 / 2

Cot θ = 2√2

8 0
3 years ago
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