Explanation:
It is known that formula for the ionization energy of hydrogen atom is as follows.
E =
or, n =
The value of energy is given as 0.544 eV. Therefore, we will calculate the value of n as follows.
n =
=
= 5
Thus, we can conclude that n equals to 5 for a hydrogen atom if 0.544 eV of energy can ionize it.
Answer:
Explanation:
Group 4A contains a total of 4 electrons for each atom in their valence shell. Filling the orbital diagram, let's say, for carbon, notice that when we start with period 2, we have two elements in the s-block, that is, lithium and beryllium. They correspond to the two s electrons that belong to the valence shell of carbon.
Moving on, we have boron and carbon, the remaining 2 electrons. Now, starting with boron, we're in the p-block.
That said, looking at the second period, the electron configuration for the valence shell of a group 4A element would be: