Balanced equation:
Al2(SO4)3 +3 Ca(OH)2 ---> 2Al(OH)3 + 3CaSO4?
Check:
Left side: Al:2; [SO4]: 3; Ca: 3; [OH] 3*2 = 6
Rigth side: Al: 2; [OH]: 2*3 = 6; Ca:3; [SO4]: 3
Mole ratio of Ca(OH)2 : Al (OH)3
3 moles of Ca(OH)2: 2moles of Al(OH)3 = 3:2
Answer: Option B.
Answer:
0.00369 moles of HCl react with carbonate.
Explanation:
Number of moles of HCl present initially =
moles = 0.00600 moles
Neutralization reaction (back titration): 
According to above equation, 1 mol of NaOH reacts with 1 mol of 1 mol of HCl.
So, excess number of moles of HCl present = number of NaOH added for back titration =
moles = 0.00231 moles
So, mole of HCl reacts with carbonate = (Number of moles of HCl present initially) - (excess number of moles of HCl present) = (0.00600 - 0.00231) moles = 0.00369 moles
Hence, 0.00369 moles of HCl react with carbonate.
Answer:
48g of Magnesium.
Explanation:
We know that:
Mole=given mass/molar mass
Then, moles of aluminum = 54/27 = 2.
A/c to question ,
For 2 moles of magnesium it's mass is 2×24=48g.
Hence, the required mass for same number of magnesium atoms is 48g.
(Hope this helps can I pls have brainlist (crown)☺️)
Hey there!
Your answer is option A.
"Molecules of the dispersion medium colliding with dispersed phase particles" is what causes Brownian motion in colloids.
Hope this helps you.
Have a great day!