Answer:
(a) 62.5 m
(b) 7.14 s
Explanation:
initial speed, u = 35 m/s
g = 9.8 m/s^2
(a) Let the rocket raises upto height h and at maximum height the speed is zero.
Use third equation of motion
h = 62.5 m
Thus, the rocket goes upto a height of 62.5 m.
(b) Let the rocket takes time t to reach to maximum height.
By use of first equation of motion
v = u + at
0 = 35 - 9.8 t
t = 3.57 s
The total time spent by the rocket in air = 2 t = 2 x 3.57 = 7.14 second.
To find the scientific notation, you need to divide at the decimal by the power of 10. So since there are 2 powers of 10, what you want to do is move the decimal 2 places to the left which will give you: .054
Answer:5.075N
Explanation:
Mass=0.145kg
Acceleration=35m/s^2
Force=mass x acceleration
Force=0.145 x 35
Force=5.075N
Answer:
The tendeny of a body to continue its state either motion or rest is called inertia . First law of newton also called law of inertia .
There are three types of inertia
1. Motion inertia
2. Rest inertia
3. Directional inertia
Explanation:
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