I would assume air resistance is negligible and so the acceleration of the package would be approximately 9.81 m/s².
Taking downwards as positive, use v²=u²+2as.
v²=(-2)²+2(9.81)(14)
v=16.7 m/s
Answer:
The answer to your question is: letter D.
Explanation:
a.The mass that a mole of substance has, measured in grams per mole. Density is not measure in moles, so this is not the correct answer.
b.The amount of substance dissolved in a liquid, measured in moles per liter. The substance dissolved in a liquid must be measure in grams not in moles, so this answer is incorrect.
c.The mass of substance dissolved in a liquid, measured in grams per milliliter. I think that this definition is correct but is incomple, so this answer is wrong.
d.The ratio of a substance's mass to its volume, measured in grams per milliliter and also equivalent to grams per cubic centimeter. This is the right description to density, so this is the correct answer.
The first law states that “objects at rest and objects in motion remain in motion in a straight line unless acted upon by an unbalanced force”. Keeping the ice smooth will make sure there is not friction, friction would slow the puck down
Answer:
Initial Velocity is 4 m/s
Explanation:
What is acceleration?
It is the change in velocity with respect to time, or the rate of change of velocity.
We can write this as:
![a=\frac{\Delta v}{t}](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B%5CDelta%20v%7D%7Bt%7D)
Where
a is the acceleration
v is velocity
t is time
is "change in"
For this problem , we are given
a = 1.2
t = 10
Putting into formula, we get:
![a=\frac{\Delta v}{t}\\1.2=\frac{\Delta v}{10}\\\Delta v = 1.2*10\\\Delta v = 12](https://tex.z-dn.net/?f=a%3D%5Cfrac%7B%5CDelta%20v%7D%7Bt%7D%5C%5C1.2%3D%5Cfrac%7B%5CDelta%20v%7D%7B10%7D%5C%5C%5CDelta%20v%20%3D%201.2%2A10%5C%5C%5CDelta%20v%20%3D%2012)
So, the change in velocity is 12 m/s
The change in velocity can also be written as:
![\Delta v = Final \ Velocity - Initial \ Velocity](https://tex.z-dn.net/?f=%5CDelta%20v%20%3D%20Final%20%20%5C%20Velocity%20-%20Initial%20%5C%20Velocity)
It is given Final Velocity = 16, so we put it into formula and find Initial Velocity. Shown Below:
![\Delta v = Final \ Velocity - Initial \ Velocity\\12=16-Initial \ Velocity\\Initial \ Velocity = 16 - 12 = 4](https://tex.z-dn.net/?f=%5CDelta%20v%20%3D%20Final%20%20%5C%20Velocity%20-%20Initial%20%5C%20Velocity%5C%5C12%3D16-Initial%20%5C%20Velocity%5C%5CInitial%20%5C%20Velocity%20%3D%2016%20-%2012%20%3D%204)
hence,
Initial Velocity is 4 m/s