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allochka39001 [22]
3 years ago
5

HEY CAN ANYONE PLS ANSWER THESE QUESTION!!!!!

Physics
1 answer:
Pie3 years ago
5 0

1. A model can come in many shapes, sizes, and styles.

✅

2. Models can help scientists communicate their ideas, understand processes, and make predictions.

✅

3. Thomson's experiments with cathode ray tubes showed that all atoms contain tiny negatively charged subatomic particles or electrons.

✅

4. The plum pudding model has electrons surrounded by a volume of positive charge

✅

5. Electrons are kept in the orbit around the nucleus by the electromagnetic         force.

IamSugarbee

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A solid uniform cylinder is rolling without slipping. What fraction of its kinetic energy is rotational?
tester [92]

Answer:

Explanation:

Let m be the mass of cylinder and r be the radius. It is moving with velocity v and angular velocity is ω. Let I be the moment of inertia of the cylinder.

I = 0.5 mr²

Total kinetic energy, T = 0.5 mv² + 0.5 Iω²

T = 0.5 (mv² + 0.5 mr²ω²)

v = rω

So, T = 0.5 (mv² + 0.5 mv²) = 0.75 mv²

Rotational kinetic energy is

R = 0.5 Iω² = 0.5 x 0.5 mr²ω²

R = 0.25 mv²

So, R / T = 0.25 / 0.75 = 1/3

5 0
3 years ago
Please guys i need help in this
JulijaS [17]

Answer:

10 seconds

Explanation:

We have the equation V = at  (speed = acceleration x time)

We want to find the time, so can rearrange to T = V/a (time = speed / acceleration).

From the question, we know V is 5 and a is 0.5.

Now we can substitute that into our equation: 5/0.5 = 10.

So the time is 10 seconds.

Hope this helps! Let me know if you have any questions :)

8 0
3 years ago
A car (mass = 1200 kg) is traveling at 31.1 m/s when it collides head-on with a sport utility vehicle (mass = 2830 kg) traveling
IrinaVladis [17]

Answer:

13.18 m/s

Explanation:

Let the velocity of sports utility car is

-u as it is moving in opposite direction.

mc = 1200 kg, uc = 31.1 m/s

ms = 2830 kg, us = - u = ?

Using conservation of momentum

mc × uc + ms × us = 0

1200 × 31.1 - 2830 × u = 0

u = 13.18 m/s

4 0
3 years ago
3 physical adaptations of a frog
ICE Princess25 [194]
Water, land. breath using skin and lungs
6 0
3 years ago
A permanent magnet has a magnetic dipole moment of 0.160 A · m^2. The magnet is in the presence of an external uniform magnetic
Elena L [17]

Answer:

the magnitude of the torque  on the permanent magnet = 7.34×10⁻³ Nm

the potential energy (in J) of the system consisting of the permanent magnet and the magnetic field provided by the coils =  -1.0485 ×10⁻² J

Explanation:

The torque is given by :

\bar {N} = \bar {m} * \bar {B}

where ;

m = 0.160 A.m²

B = 0.0800 T

θ = 35°

So the magnitude of the torque N = mBsinθ

N = (0.160)(0.0800)(sin 35°)

N = 0.007341

N = 7.34×10⁻³ Nm

Hence, the magnitude of the torque  on the permanent magnet = 7.34×10⁻³ Nm

b) The potential energy \bar{U} = \bar{-m} * \bar{B}

U = -mBcosθ

U = (- 0.160)(0.0800)(cos 45)

U = -0.010485

U = -1.0485 ×10⁻² J

Thus, the potential energy (in J) of the system consisting of the permanent magnet and the magnetic field provided by the coils =  -1.0485 ×10⁻² J

6 0
3 years ago
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