All categories

4 years ago

HEY CAN ANYONE PLS ANSWER THESE QUESTION!!!!!

Physics

1 answer:

Pie4 years ago

5 0

1. A model can come in many shapes, sizes, and styles.

✅

2. Models can help scientists communicate their ideas, understand processes, and make predictions.

✅

3. Thomson's experiments with cathode ray tubes showed that all atoms contain tiny negatively charged subatomic particles or electrons.

✅

4. The plum pudding model has electrons surrounded by a volume of positive charge

✅

5. Electrons are kept in the orbit around the nucleus by the electromagnetic force.

IamSugarbee

You might be interested in

Show dispersion of white light through a glass prism and describe the activity .

Brilliant_brown [7]

Answer:

The phenomenon of splitting of white light into its seven constituent colours when it passes through a glass prism is called dispersion of white light. The various colours seen are Violet, Indigo, Blue, Green, Yellow, Orange and Red.

Explanation:

6 0

3 years ago

Read 2 more answers

A 4.67-g bullet is moving horizontally with a velocity of +357 m/s, where the sign + indicates that it is moving to the right (s

Leni [432]

Answer:

(a)0.531m/s

(b)0.00169

Explanation:

We are given that

Mass of bullet, m=4.67 g= $4.67\times 10^{-3} kg$

1 kg =1000 g

Speed of bullet, v=357m/s

Mass of block 1, $m_1=1177g=1.177kg$

Mass of block 2, $m_2=1626 g=1.626 kg$

Velocity of block 1, $v_1=0.681m/s$

(a)

Let velocity of the second block after the bullet imbeds itself=v2

Using conservation of momentum

Initial momentum=Final momentum

$mv=m_1v_1+(m+m_2)v_2$

$4.67\times 10^{-3}\times 357+1.177(0)+1.626(0)=1.177\times 0.681+(4.67\times 10^{-3}+1.626)v_2$

$1.66719=0.801537+1.63067v_2$

$1.66719-0.801537=1.63067v_2$

$0.865653=1.63067v_2$

$v_2=\frac{0.865653}{1.63067}$

$v_2=0.531m/s$

Hence, the velocity of the second block after the bullet imbeds itself=0.531m/s

(b)Initial kinetic energy before collision

$K_i=\frac{1}{2}mv^2$

$k_i=\frac{1}{2}(4.67\times 10^{-3}\times (357)^2)$

$k_i=297.59 J$

Final kinetic energy after collision

$K_f=\frac{1}{2}m_1v^2_1+\frac{1}{2}(m+m_2)v^2_2$

$K_f=\frac{1}{2}(1.177)(0.681)^2+\frac{1}{2}(4.67\times 10^{-3}+1.626)(0.531)^2$

$K_f=0.5028 J$

Now, he ratio of the total kinetic energy after the collision to that before the collision

= $\frac{k_f}{k_i}=\frac{0.5028}{297.59}$

=0.00169

5 0

3 years ago

When two volleyball players strike the ball on opposite sides of the net with the same amount of force, what happens?

cricket20 [7]

Answer:

The net force is zero because both volleyball players are hitting the ball with same force.

Explanation:

8 0

3 years ago

a car going at 30 m/s undergoes an acceleration of 2 m/(s^2) for 4 seconds. how far did it travel while accelerating?

Naily [24]

V=v0+at=38m/s; v^2=v0^2+2ad=>d=(v^2-v0^2)/2a=544/4=68m

5 0

3 years ago

Calculate the final velocity of an object, given that:

Luba_88 [7]

64. 16x16 = 4 so 9x9 divided by 2 equals 7

7 0

3 years ago