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3 years ago

HEY CAN ANYONE PLS ANSWER THESE QUESTION!!!!!

Physics

1 answer:

Pie3 years ago

5 0

1. A model can come in many shapes, sizes, and styles.

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2. Models can help scientists communicate their ideas, understand processes, and make predictions.

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3. Thomson's experiments with cathode ray tubes showed that all atoms contain tiny negatively charged subatomic particles or electrons.

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4. The plum pudding model has electrons surrounded by a volume of positive charge

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5. Electrons are kept in the orbit around the nucleus by the electromagnetic force.

IamSugarbee

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A sensitive gravimeter at a mountain observatory finds that the free-fall acceleration is 0.0055 m/s2 less than that at sea leve

pshichka [43]

Gs*rs^2 = gm*rm^2
rm = rs*√gs/gm 
rm = 6370*√9.83/(9.83-0.009) = 6372.92 
mountain observatory is placed at an altitude worth 2920 m asl

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4 years ago

The space station is 4.41 x 10^5 kg and orbits the earth 6.78 x 10^6 m from the center of earth. The mass of earth is 5.97 x 10^

allochka39001 [22]

Answer:

3 820 885 N

Explanation:

Gravitational equation

F = G m1 m2 / r^2

G = gravitational constant = 6.6713 x 10^-11 m^3/kg-s^2

F = 6.6713 x 10^-11 * 4.41 x 10^5 * 5.97 x 10^24 / ( 6.78x 10^6)^2

= 3820885 .3 N

6 0

2 years ago

What type of nuclear decay releases energy but not a particle?

statuscvo [17]

I believe gamma decay but i may be wrong

7 0

3 years ago

Read 2 more answers

I would love to stretch a wire from our house to the Shop so I can 'call' my husband in for meals. The wire could be tightened t

dezoksy [38]

Note: I'm not sure what do you mean by "weight 0.05 kg/L". I assume it means the mass per unit of length, so it should be "0.05 kg/m".

Solution:
The fundamental frequency in a standing wave is given by
$f= \frac{1}{2L} \sqrt{ \frac{T}{m/L} }$
where L is the length of the string, T the tension and m its mass. If we plug the data of the problem into the equation, we find
$f= \frac{1}{2 \cdot 24 m} \sqrt{ \frac{240 N}{0.05 kg/m} }=1.44 Hz$

The wavelength of the standing wave is instead twice the length of the string:
$\lambda=2 L= 2 \cdot 24 m=48 m$

So the speed of the wave is
$v=\lambda f = (48 m)(1.44 Hz)=69.1 m/s$

And the time the pulse takes to reach the shop is the distance covered divided by the speed:
$t= \frac{L}{v}= \frac{24 m}{69.1 m/s}=0.35 s$

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4 years ago

An iron nail goes through a chemical change when iron in the nail combines with oxygen in the air to form iron oxide. This compo

Mazyrski [523]

It is like that, except most nails are steel or stainless steel, slowing to rusting process to about 5 years.

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3 years ago