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Assoli18 [71]
3 years ago
10

The Federal Communications Commission (FCC) has considered lifting the ban on in-flight cell phone use. This could allow people

to have conversations on their cell phones during plane flights. Give your opinion. Should the FCC allow in-flight calls? Why or why not?
Physics
2 answers:
olga nikolaevna [1]3 years ago
7 0
I would say that there shouldn't be any calls on a plane while in-flight because you never know what someone is calling for. It can lead to a bad situation like 9/11 or any form of terrorism. 
alekssr [168]3 years ago
6 0
Oh please ! Imagine trying to read or sleep while the yo-yo next to you or across the aisle is yammering incessantly at the top of his lungs. It would be like a screaming baby kicking the back of your seat, ALL flight and EVERY flight.

Besides ... the cellular system is designed to provide coverage on the ground, not in the air. I think every call you made from an airliner would drop in a minute ar two.

There's no right or wrong answer to a "should" question. My humble OPINION is: Please, not until Satan's inferno freezes over !
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A ball is thrown with a speed of 20 m/s at an angle of 40o above the horizontal from the top of a 22-m tall building.
MrRissso [65]

Answer:

(a). The distance is  49.79 m.

(b). The speed of the ball is 24.39 m/s.

Explanation:

Given that,

Speed = 20 m/s

Angle = 40°

Height = 22 m

Time = 3.25 sec

(a). We need to calculate the distance

Using formula of distance

d=u\cos\theta\times t

Put the value into the formula

d=20\cos40\times3.25

d=49.79\ m

(b). We need to calculate the horizontal velocity

Using formula of velocity

v_{x}=u\cos\theta

Put the value into the formula

v_{x}=20\times\cos40

v_{x}=15.3\ m/s

We need to calculate the vertical velocity

Using equation of motion

v_{y}=u\sin\theta-gt

Put the value into the formula

v_{y}=20\sin40-9.8\times3.25

v_{y}=-19\ m/s

Negative sign shows the opposite direction.

We need to calculate the speed of ball

Using formula of speed

v=\sqrt{v_{x}^2+v_{y}^2}

v=\sqrt{(15.3)^2+(19)^2}

v=24.39\ m/s

Hence, (a). The distance is  49.79 m.

(b). The speed of the ball is 24.39 m/s.

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Answer:

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Explanation:

The boiling point of water is much higher than that of either nitrogen or oxygen gas . So when the mixture is condensed  to a temperature lower than

100°C , water vapor will come out first in the form of water leaving other

elements of mixture in gaseous phase. In this way, water vapor will get separated from others.

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