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Assoli18 [71]
4 years ago
10

The Federal Communications Commission (FCC) has considered lifting the ban on in-flight cell phone use. This could allow people

to have conversations on their cell phones during plane flights. Give your opinion. Should the FCC allow in-flight calls? Why or why not?
Physics
2 answers:
olga nikolaevna [1]4 years ago
7 0
I would say that there shouldn't be any calls on a plane while in-flight because you never know what someone is calling for. It can lead to a bad situation like 9/11 or any form of terrorism. 
alekssr [168]4 years ago
6 0
Oh please ! Imagine trying to read or sleep while the yo-yo next to you or across the aisle is yammering incessantly at the top of his lungs. It would be like a screaming baby kicking the back of your seat, ALL flight and EVERY flight.

Besides ... the cellular system is designed to provide coverage on the ground, not in the air. I think every call you made from an airliner would drop in a minute ar two.

There's no right or wrong answer to a "should" question. My humble OPINION is: Please, not until Satan's inferno freezes over !
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Who can help me for this question plz:(
Vanyuwa [196]
Force = mass x acceleration

15 = mass x 4

Mass = 15/4

Mass = 3.75 Kg
8 0
3 years ago
A very long conducting cylinder (length L) of radius R(R<R and (b)r
mina [271]

Answer:

Explanation:

We have to find electric potential V at a distance r.

a) For r>R,

The electric field in the cylinder is given by

E.A equating it to the other electric field given by

б.A/ε₀

Here the area of cylinder is given by= 2*3.14*r*L

While for the outside, the area= 2*3.14*R*L

Equating both, we get

E= бR/rε₀

Now,

The potential difference is given as:

ΔV= -бR/rε₀ and integrating right side with respect to dr under limits r and R.

Where ΔV= V₀-V

So solving we get

V₀=V-бR/ε₀ln (r/R)

b) For r<R i.e. inside the cylinder

There will be no electric field produced as E=0

So ultimately Vin= V

c) V=0 at r= infinity.

4 0
3 years ago
) In the figure below, three charges K, L and M are placed at the corners of an equilateral triangle. If K and L are fixed, in w
abruzzese [7]

Answer:

B)

Explanation:

Negative (-) charge M will not move towards negative (-) charge K because, same charges will not attract each other in the given case

Negative (-) charge at the M tends to move towards positive (+) charge L in the direction of B) because opposite charges attract each other.

4 0
3 years ago
The knee extensors insert on the tibia at an angle of 30 degrees (from the longitudinal axis of the tibia), at a distance of 3 c
Reika [66]

Answer:

the knee extensors must exert 15.87 N

Explanation:

Given the data in the question;

mass m = 4.5 kg

radius of gyration k = 23 cm = 0.23 m

angle ∅ = 30°

∝ = 1 rad/s²

distance of 3 cm from the axis of rotation at the knee r = 3 cm = 0.03 m

using the expression;

ζ = I∝

ζ = mk²∝

we substitute

ζ = 4.5 × (0.23)² × 1

ζ  = 0.23805 N-m

so

from; ζ = rFsin∅

F = ζ / rsin∅

we substitute

F = 0.23805 / (0.03 × sin( 30 ° )

F = 0.23805 / (0.03 × 0.5)

F F = 0.23805 / 0.015

F = 15.87 N

Therefore, the knee extensors must exert 15.87 N

7 0
3 years ago
In which situation is chemical energy being converted to another form of energy?
otez555 [7]

Answer:

A burning candle. (chemical energy into energy of heat and light, i.e. thermal and wave)

Explanation:

5 0
3 years ago
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