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Assoli18 [71]
4 years ago
10

The Federal Communications Commission (FCC) has considered lifting the ban on in-flight cell phone use. This could allow people

to have conversations on their cell phones during plane flights. Give your opinion. Should the FCC allow in-flight calls? Why or why not?
Physics
2 answers:
olga nikolaevna [1]4 years ago
7 0
I would say that there shouldn't be any calls on a plane while in-flight because you never know what someone is calling for. It can lead to a bad situation like 9/11 or any form of terrorism. 
alekssr [168]4 years ago
6 0
Oh please ! Imagine trying to read or sleep while the yo-yo next to you or across the aisle is yammering incessantly at the top of his lungs. It would be like a screaming baby kicking the back of your seat, ALL flight and EVERY flight.

Besides ... the cellular system is designed to provide coverage on the ground, not in the air. I think every call you made from an airliner would drop in a minute ar two.

There's no right or wrong answer to a "should" question. My humble OPINION is: Please, not until Satan's inferno freezes over !
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Can we write names while writing conversation in board exam​
lora16 [44]

Answer:

ya we can write the imaginary character's name .

So that we  can identify these imaginary people, as we cannot simply write the conversation and leave it .

Or maybe sometimes the reader will get confused as there is no name for the two people .

So, i suggest that you should write the names

Explanation:

You can even ask to your class teacher for further clarification

5 0
3 years ago
The vapor pressure of ethanol at 293 K is 5.95 kPa and at 336.5 K it is 53.3 kPa. Calculate the enthalpy of vaporization of etha
denis-greek [22]

Answer:

H=41.3kJmol^{-1}

Explanation:

The equation relating the the enthalphy, pressure and temperature is expressed as

ln(\frac{P_{2}}{P_{1}} )=\frac{H}{R}(\frac{1}{T_{1}}-\frac{1}{T_{2}} ) \\

Where P is the pressure, H is the enthalphy, and T is the temperature.

since the given values are

T_{1}=293k, \\T_{2}=336.5k\\P_{1}=5.95kPA\\p_{2}=53.3kPA\\and R=8.314J.K^{-1}mol_{-1}

if we insert values, we arrive at

ln(\frac{53.3}{5.95} )=\frac{H}{8.314}(\frac{1}{293}-\frac{1}{336.5} )\\2.19=\frac{H}{8.314}(0.00044)\\H=(2.19*8.314)/0.00044\\H=41,268.8Jmol^{-1}\\H=41.3kJmol^{-1}

4 0
3 years ago
1.
Brilliant_brown [7]

Answer:

1) solvent

2) liquid-solid

3) gas - gas

Explanation:

1) A solution is the homogenous mixture of two or more substances in such a way that its components are uniformly distributed. In any solution, the solvent make up the greatest quantity or volume while the solute is of lesser quantity.

2) liquid-solid is the most common type of solution.

3) A gas solution can be a gas dissolved in a gas, or a liquid dissolved in a gas, or a solid dissolved in a gas.  Air is a gas - gas solution, it is composed of oxygen and other dissolved gases in nitrogen

6 0
3 years ago
The valence electron occur in what part of the atom
Burka [1]
<span>The valence electrons occur in the outer shell of the atom. </span>
5 0
3 years ago
1. A 700 kg satellite is in orbit 2.4 x 106 meters from the center of the Earth. What is the force of
nevsk [136]

Answer:

4.8 \cdot 10^4 N

Explanation:

The force of gravity acting on the satellite is given by:

F=\frac{GMm}{r^2}

where

G is the gravitational constant

M=5.98\cdot 10^{24} kg is the Earth's mass

m is the mass of the satellite

r is the distance of the satellite from the Earth's centre

Here we have

m = 700 kg

r=2.4\cdot 10^6 m

Substituting into the equation, we find:

F=\frac{(6.67\cdot 10^{-11})(5.98\cdot 10^{24})(700)}{(2.4\cdot 10^6)^2}=4.8 \cdot 10^4 N

<em>Note that the distance mentioned in the problem (2.4 x 10^6 meters) is not realistic, since it is less than the radius of the Earth (6.37 x 10^6 meters).</em>

3 0
3 years ago
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