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Semmy [17]
3 years ago
13

1. What are three questions you should ask before joining a club?

Physics
1 answer:
lara [203]3 years ago
7 0

Answer:

what time does it start.

what do I need to join.

what are your expectations.

You might be interested in
Science please helppp
Daniel [21]

The red box must way more. Gravitational potential energy is the product of a an objects mass times the acceleration due to gravity (which is constant on earth) times its height. Since the objects are on the same shelf they are at the same height, and since gravitational acceleration is constant as long as we stay on planet earth, then the mass is the only possible thing that could have changed. This means that the red box must weigh more than the blue box.

3 0
3 years ago
A circular window of 30 cm diameter in a submarine can withstand a maximum force of 5.20 × 105 N. The maximum depth in a lake to
Svetach [21]

Answer: Option (b) is the correct answer.

Explanation:

The given data is as follows.

         F = 5.20 \times 10^{5} N

         g = 9.8 m/s

         radius = \frac{diameter}{2}

                    = \frac{30 cm}{2} = 15 cm = 0.15 m   (as 1 m = 100 cm)

Formula to calculate depth is as follows.

        F = \rho \times g \times h \times A

or,      h = \frac{F}{\rho \times g \times A}        

       h = \frac{5.2 \times 10^{5}}{1000 \times 9.8 \times (3.1416 \times (0.15 m^{2})}

           = 751 m

Thus, we can conclude that the maximum depth in a lake to which the submarine can go without damaging the window is closest 750 m.

3 0
3 years ago
While bats emit a wide variety of sounds, one type emits pulses of sound at a frequency between 39 kHz and 78 kHz. What is the r
sdas [7]

Answer:

The range of wavelengths of the sound is 7692.30 m and 3846.15 m

Explanation:

A bat emits pulses of sound at a frequency between 39 kHz and 78 kHz. It is required to find the range of wavelengths of this sound.

Bat uses ultrasonic waves. It moves with the speed of light.

If f = 39 kHz,

\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{39\times 10^3}\\\\\lambda=7692.30\ m

If f = 78 kHz,

\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{78\times 10^3}\\\\\lambda=3846.15\ m

So, the range of wavelengths of the sound is 7692.30 m and 3846.15 m.

6 0
3 years ago
Earlier we discussed the concept of isostasy, where lower density rocks rise higher than higher density rocks. How is the variat
Elena L [17]

The variation of water depth at spreading centers (ridges) controlled by isostasy  as convective cooling cools the rocks much more effectively the than heat conduction.

<h3>What is convective heat transfer?</h3>

When heat transfer takes place between the two fluids in direct or indirect contact.

The lithosphere cools when it moves away from the ridge axis by sea floor spreading. The cooler rocks have low density, so the sea floor gets deeper as the lithosphere gets more dense.

Thus, the convective cooling cools the rocks much more effectively the than heat conduction.

Learn more about convective heat transfer

brainly.com/question/10219972

#SPJ1

4 0
2 years ago
Car a with mass 1,783 kg collides with stationary 1600 kg car b. they become locked together after the collision and move with s
ValentinkaMS [17]

The initial speed of car A is 15.18 m/s.

Momentum is defined as mass in motion. If there are two objects (the two objects in motion or only one object in motion and the other in stationary) that collide and no other forces work in the system, the law of momentum conservation applies in the system.

p=p'

pa+pb = pa'+pb'

(ma×va) + (mb×vb) = (ma×va') + (mb×vb')

  • ma = mass of object A (kg) = 1,783 kg
  • mb = mass of object B (kg) = 1,600 kg
  • va = speed of object A before collides (m/s)
  • va' = speed of object A after collides (m/s) = 8 m/s
  • vb = speed of object B before collides (m/s) = 0 m/s
  • vb' = speed of object B after collides (m/s) = 8 m/s
  • p = momentum before collision (Ns)
  • p' = momentum after collision (Ns)

(ma×va) + (mb×vb) = (ma×va') + (mb×vb')

(1,783×va) + (1,600×0) = (1,783×8) + (1,600×8)

(1,783×va) + 0 = 14,264+12,800

(1,783×va) = 27,064

va \:=\: \frac{27,064}{1.783}

va = 15.18 m/s

Learn more about The law of momentum conservation here: brainly.com/question/7538238

#SPJ4

3 0
1 year ago
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