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3 years ago

1. What are three questions you should ask before joining a club?

Physics

1 answer:

lara [203]3 years ago

7 0

Answer:

what time does it start.

what do I need to join.

what are your expectations.

You might be interested in

You place an ice cube of mass 7.50×10−3kg and temperature 0.00∘C on top of a copper cube of mass 0.220 kg. All of the ice melts,

g100num [7]

Answer:

$T = 29.66 ^o C$

Explanation:

As we know that here final equilibrium temperature is 0 degree C

so we can use energy conservation here

heat given by the cube = heat absorbed by the ice

so we have

$ms \Delta T = m' L$

so here we have

$0.220(385)(T - 0) = (7.50 \times 10^{-3})(3.35 \times 10^5)$

$T = \frac{2512.5}{0.220 \times 385}$

$T = 29.66 ^o C$

5 0

3 years ago

A 970-kg sports car collides into the rear end of a 2300-kg SUV stopped at a red light. The bumpers lock, the brakes are locked,

vlabodo [156]

Answer:

22.73 m/s or 81.72 kph

Explanation

We can find the combined mass of both cars as

970 kg + 2300 kg = 3270 kg.

Then the normal force of the cars can be calculated as

F(n)= mg

Where g is acceleration due to gravity 9.8m/s^2

3270 kg ×9.8 = 32046 kg*m/s^2.

coefficient of kinetic friction between tires and road to be 0.80 × F(n)

Then the frictional force can be calculated as

= (32046kg*m/s^2 × 0.80 )

= 25636.8 kg*m/s^2

We can now calculate the work done that was used stopping the cars as

Frictional force × distance

(25636.8 kg*m/s^2 ) × 2.9m= 74346.72kg*m^2/s^2

From kinetic energy formula, the combined velocity of the car can be determined

E=0.5 M V²

√(2E/M) = V

√(2*74346.72kg*m^2/s^2 / 3270 kg) = V

V= √ (45.472)

V=6.743293m/s

the momentum of both cars can be determined as

6.743293m/s * 3270 kg

= 22050.57kg*m/s

Now the final momentum of both cars must be equal to the the momentum of

the sports car just prior to the collision. Therefore, the speed of the sports car at impact.

=(22050.57 kg*m/s) / 970 kg = 22.73 m/s

We can convert that to km/h.

22.73 m/s * 3600 s/h / 1000 m/km = 81.72 kph

7 0

2 years ago

Cousin Throckmorton is playing with the clothesline. One end of the clothesline is attached to a vertical post. Throcky holds th

Oksi-84 [34.3K]

Answer:

The frequencies are $f_n = n (0.875 )$

Explanation:

From the question we are told that

The speed of the wave is $v = 0.700 \ m/s$

The length of vibrating clothesline is $L = 40.0 \ cm = 0.4 \ m$

Generally the fundamental frequency is mathematically represented as

$f = \frac{v}{2 L }$

=> $f = \frac{ 0.700 }{2 * 0.4 }$

=> $f = 0.875 \ Hz$

Now this other frequencies of vibration experience by the clotheslines are know as harmonics and they are obtained by integer multiple of the fundamental frequency

The frequencies are mathematically represented as

$f_n = n * f$

=> $f_n = n (0.875 )$

Where n = 1, 2, 3 ....

3 0

3 years ago

Whenever an object is moving at a constant rate, the value(s) that equal zero is (are):

dolphi86 [110]

Answer:

d) all of the above

Explanation:

the speed, velocity, and acceleration all changes to 0 due to no motion.

5 0

3 years ago

Read 2 more answers

What does the energy of an electromagnetic wave depend on?

Mrrafil [7]

It depends on frequency

6 0

2 years ago