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ryzh [129]
3 years ago
15

What is the value of the energy (in Joules) stored by the mobile phone battery (capacity of 1.8 Ah), if it is rated at 3.7 V

Engineering
2 answers:
balandron [24]3 years ago
7 0

Answer:

6.6 Joules

Explanation:

Energy = power * time

= V*I*t

= 3.7 * 1.8

= 6.6 Joules

joja [24]3 years ago
4 0

Answer:

E=23,976 J

Explanation:

Given that

I = 1.8 Ah

Voltage =  3.7 V

We know that 1 h = 3600 s

I = 1.8 x 3600 A.s

I=6480 A.s

The energy in Jules given as

E= V. I  

We know that unit of V.I is Watts ( J/s) and when multiple by seconds then we get Joules.

E=3.7 x 6480 Watt.s

E=23,976 J

Therefore the energy in joule will be 23,976 J.

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Twenty-five wooden beams were ordered or a construction project. The sample mean and he sample standard deviation were measured
aksik [14]

Answer:

Correct option: B. 90%

Explanation:

The confidence interval is given by:

CI = [\bar{x} - z\sigma_{\bar{x}} , \bar{x}+z\sigma_{\bar{x}} ]

If \bar{x} is 190, we can find the value of z\sigma_{\bar{x}}:

\bar{x} - z\sigma_{\bar{x}}  = 188.29

190 - z\sigma_{\bar{x}}  = 188.29

z\sigma_{\bar{x}}  = 1.71

Now we need to find the value of \sigma_{\bar{x}}:

\sigma_{\bar{x}} = s / \sqrt{n}

\sigma_{\bar{x}} = 5/ \sqrt{25}

\sigma_{\bar{x}} = 1

So the value of z is 1.71.

Looking at the z-table, the z value that gives a z-score of 1.71 is 0.0436

This value will occur in both sides of the normal curve, so the confidence level is:

CI = 1 - 2*0.0436 = 0.9128 = 91.28\%

The nearest CI in the options is 90%, so the correct option is B.

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With 64 KB of memory and 8 bits in each memory location, how wide should the address bus be to access all 64 KB of memory? (k =
marishachu [46]

Answer:

16-bit wide

Explanation:

In order to find the width of the address bus, we need first to know how many memory cells it is needed to address.

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64 KB = 2⁶ * 2¹⁰ bytes = 2¹⁶ bytes.

In order to address this quantity of cell positions, the address bus must be able to address 2¹⁶ bytes, so it must have 16-bit wide.

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