Answer:
The magnitude of the magnetic field halfway between the wires is 3.0 x 10⁻⁵ T.
Explanation:
Given;
distance half way between the parallel wires, r = ¹/₂ (40 cm) = 20 cm = 0.2 m
current carried in opposite direction, I₁ and I₂ = 10 A and 20 A respectively
The magnitude of the magnetic field halfway between the wires can be calculated as;
where;
B is magnitude of the magnetic field halfway between the wires
I₁ is current in the first wire
I₂ is current the second wire
μ₀ is permeability of free space
r is distance half way between the wires
Therefore, the magnitude of the magnetic field halfway between the wires is 3.0 x 10⁻⁵ T.
It would take 500 seconds, because 2500 divided by 5 is 500
Answer: 4m/s²
Explanation:
At stop signal car speed iz 0 ; V1=0m/s
After t=5s , car has speed is V2=20m/s
using:
a=(V2-V1)/t
a=(20m/s-0m/s)/5s
a=20m/s/5s
a=4m/s²
<h3><u>Answer;</u></h3>
Choose a heavier bat
<h3><u>Explanation</u>;</h3>
- Momentum is a vector which is often defined as the product of an object’s mass with its velocity.
- Two factors affecting momentum is the mass and velocity of the object. An object that has a low velocity and a small mass produce minimal momentum because it would take a small force and/or time to stop it.
- Therefore, choosing a heavier bat would increase the momentum of the plate.