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ivanzaharov [21]

3 years ago

9

The change in a pitch of a sound as an object moves closer or farther away is a result of

1 answer:

MrMuchimi3 years ago

4 0

The Doppler effect is a change in the frequency of sound waves that occurs when the source of the sound waves is moving relative to a stationary listener. As the source of sound waves approaches a listener, the sound waves get closer together, increasing their frequency and the pitch of the sound.

I’m hope this help

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Josh has a toy car of mass 3 kg tied to a string of length 2 m. He ties the string to a pole and has the toy car drive in a circ

gulaghasi [49]

Part a)

Centripetal acceleration is defined as

$a_c = \frac{v^2}{R}$

now here we know that

$v = 3m/s$

$R = 2 m$

m = 3 kg

now from above formula we have

$a_c = \frac{3^2}{2}$

$a_c = 4.5 m/s^2$

Part b)

Maximum possible tension in the string is given as

$T = 50 N$

now by force equation we have

$F = ma$

$50 = 3 a$

$a = \frac{50}{3} m/s^2$

now again by above formula

$\frac{v^2}{R} = \frac{50}{3}$

$v = \sqrt{\frac{50 \times 2}{3}}$

$v = 5.77 m/s$

5 0

4 years ago

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At what time did time begin<br><br><br> 50 points :)

USPshnik [31]

Answer:

According to the standard big bang model of cosmology, time began together with the universe in a singularity approximately 14 billion years ago.

Explanation: the big bang

8 0

2 years ago

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A 3 kg mass object is pushed 0.6 m into a spring with spring constant 210 N/m on a frictionless horizontal surface. Upon release

Aleksandr-060686 [28]

Answer with Explanation:

We are given that

Mass of spring,m=3 kg

Distance moved by object,d=0.6 m

Spring constant,k=210N/m

Height,h=1.5 m

a.Work done to compress the spring initially= $\frac{1}{2}kx^2=\frac{1}{2}(210)(0.6)^2=37.8J$

b.

By conservation law of energy

Initial energy of spring=Kinetic energy of object

$37.8=\frac{1}{2}(3)v^2$

$v^2=\frac{37.8\times 2}{3}$

$v=\sqrt{\frac{37.8\times 2}{3}}$

v=5.02 m/s

c.Work done by friction on the incline, $w_{friction}=P.E-spring \;energy$

$W_{friction}=3\times 9.8\times 1.5-37.8=6.3 J$

3 0

3 years ago

A car with an initial velocity of O m/s and a mass of 1500 kg reaches a velocity of 15 m/s in 5

Flura [38]

Answer:the answer can be find out by the following steps;

Explanation:

3 0

3 years ago

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A car travels 90 km per hour how many how many Kilometres of distance does it travel in one second

gavmur [86]

Answer:

Its Moving at a constant Speed of 90km/hr

You can convert this speed to Meters/Second or Change it to Km/Second(Because we need our distance in Km)

So 90km/hr x 1/60 x1/60

=90km/3600sec

v=0.025km/sec

When an Object Moves at Constant Speed... Its displacement(distance) is given by

d=vt

given v=0.025km/sec

t=1sec

d=0.025km/sec x 1sec

d=0.025km.

7 0

3 years ago

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