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inn [45]
3 years ago
9

What are the diferent units that we typically use to measure average speed

Physics
1 answer:
Juli2301 [7.4K]3 years ago
6 0
Mph= miles per hour
kph= kilometers per hour
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initially, a particle is moving at 5.33 m/s at an angle of 37.9° above the horizontal. Two seconds later, its velocity is 6.11 m
Ainat [17]

Explanation:

Average acceleration is the change in velocity over the change in time:

a = (v − v₀) / t

In the x direction:

aₓ = (6.11 cos (-54.2°) − 5.33 cos (37.9°)) / 2.00

aₓ = -0.316 m/s²

In the y direction:

aᵧ = (6.11 sin (-54.2°) − 5.33 sin (37.9°)) / 2.00

aᵧ = -4.11 m/s²

7 0
3 years ago
The pupil of a cat's eye narrows to a slit width of 0.5 mm in daylight. What is the angular resolution of the cat's eye in dayli
Elenna [48]

Answer:

C. 10⁻³ rads

Explanation:

Here, we shall use Rayleigh's Criterion to find out the angular resolution of Cat's eye during day light. Rayleigh's Criterion is written as follows:

θ = λ/a

where,

θ = angular resolution of Cat's eye = ?

λ = wavelength = 500 nm = 5 x 10⁻⁷ m

a = slit width of eye = 0.5 mm = 5 x 10⁻⁴ m

Therefore,

θ = (5 x 10⁻⁷ m/5 x 10⁻⁴ m)

Therefore,

θ = 0.001

θ = Sin⁻¹(0.001)

θ = 0.001 rad = 1 x 10⁻³ rad

Hence, the correct answer is:

<u>C. 10⁻³ rads</u>

4 0
3 years ago
As shown in the diagram, two massless wires connect a rotating pole to a sphere of mass 7.2 kg. The sphere revolves in a horizon
11Alexandr11 [23.1K]

Use Fnet=ma. Apply it to the vertical components of all the forces acting on the ball and since tension is the same on both wires you should be able to factor it out and solve for it. Picture below

5 0
4 years ago
What energy transformations take place in Joule's system?
attashe74 [19]

The gravitational potential energy of the weight changes to motion energy when the weight moves down and the paddle wheel spins. The motion energy changes to thermal energy, causing the water’s temperature to rise.

(fast explanation for my fellow edmentum kids :))

6 0
4 years ago
Read 2 more answers
At noon, ship A is 110 km west of ship B. Ship A is sailing east at 20 km/h and ship B is sailing north at 15 km/h. How fast is
Katyanochek1 [597]

Answer:

4.47\ \text{km/h}

Explanation:

\dfrac{da}{dt} = Rate at which the distance between A and starting point of B is changing = -20 km/h

\dfrac{db}{dt} = Rate at which the distance of B is changing = 15 km/h

\dfrac{dc}{dt} = Rate at which the distance between A and B is changing

Time after which the rate at which the distance between A and B is changing is 4 hours

Distance covered by A in 4 hours = 20\times 4=80\ \text{km}

a = Distance remaining to the start point of B = 110-80=30\ \text{km}

b = Distance covered by B in 4 hours = 15\times 4=60\ \text{km}

Distance between A and B after 4 hours

c=\sqrt{a^2+b^2}\\\Rightarrow c=\sqrt{30^2+60^2}\\\Rightarrow c=67.08\ \text{km}

c^2=a^2+b^2

Differentiating with respect to time we get

c\dfrac{dc}{dt}=a\dfrac{da}{dt}+b\dfrac{db}{dt}\\\Rightarrow \dfrac{dc}{dt}=\dfrac{a\dfrac{da}{dt}+b\dfrac{db}{dt}}{c}\\\Rightarrow \dfrac{dc}{dt}=\dfrac{30\times -20+60\times 15}{67.08}\\\Rightarrow \dfrac{dc}{dt}=4.47\ \text{km/h}

The rate at which the distance between the ships is changing at 4 PM is 4.47\ \text{km/h}.

7 0
3 years ago
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