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Ions and charges= Al+3 SO3-2
The charges must add up to zero, in order for two +3 aluminum ions to cancel out three -2 sulfite ions.
Al+3 Al+3 SO3-2 SO3-2 SO3-2
<span>So simply put : </span>Al2(SO3)<span>3 </span>
Answers:
1st: 189.6 g/mol
2nd: 0.1357 L
3rd: 1.41 M
Explanation:
Finding Molar Mass:
SnCl2 = <u>Tin(II) Chloride</u>
Tin has a molar mass of <u>118.71 g/mol</u>
Chloride has a molar mass of <u>35.453 g/mol</u>
Chloride*2 = <u>70.906</u>
<u>118.71 + 70.906 ≈ 189.6 g/mol</u>
Finding Liters of Solution:
L = mL/1000
135.7 mL / 1000 = <u>0.1357</u>
Finding Molarity:
molarity = <u>moles of solute / liters of solution</u>
M = (36.4g / 189.6g) / 0.1357 L = <u>1.41 M</u>
Hope this helped ;)
Answer:
its does not
Explanation:
not do...................
Answer:
Solid ionic compounds do not conduct electricity because the ions are held firmly in place. The ions cannot move to conduct the electric current. But when an ionic compound melts, the charged ions are free to move. Therefore, molten ionic compounds do conduct electricity.
