Chemistry Help? If emission lines are created in a spectrum when an electron falls from an excited state to a relaxed state, how
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<h3>Answer:</h3>
0.0113 mol Ba(ClO₃)₂
<h3>General Formulas and Concepts:</h3><u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
<u>Chemistry</u>
<u>Atomic Structures</u>
- Reading a Periodic Table
- Using Dimensional Analysis
<u>Step 1: Define</u>
3.45 g Ba(ClO₃)₂
<u>Step 2: Identify Conversions</u>
Molar Mass of Ba - 137.33 g/mol
Molar Mass of Cl - 35.45 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of Ba(ClO₃)₂ - 137.33 + 2(35.45) + 6(16.00) = 304.33 g/mol
<u>Step 3: Convert</u>
- Set up:
- Multiply/Divide:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
0.011336 mol Ba(ClO₃)₂ ≈ 0.0113 mol Ba(ClO₃)₂
<h2>Answer:</h2>
<em>8.67kJ/mol</em>
<h2>Explanations</h2>The formula for calculating the amount of heat absorbed by the water is given as:
Determine the moles of KI
Since heat is lost, hence the enthalpy change of the solution will be negative that is:
Determine the enthalpy of solution in kJ•mol-1
Hence the enthalpy of solution in kJ•mol-1 for KI is 8.67kJ/mol
Answer:
0.05 dm³
Explanation:
Please see the attached picture for full solution.
The question is asking for the volume of H₂SO₄, so we need to find the number of moles of KOH then the number of moles of H₂SO₄. (Using mole ratio from the balanced equation) Also, potassium hydroxide is KOH not K₂SO₄ :)
