Answer:
A) pbin = 1.535 Kgm/s (+)
B) pbf = 1.696 Kgm/s (-)
C) Δp = 3.3925 Kgm/s
D) Δvr = 10.249 m/s
Explanation:
Given
Mass of the ball: m = 57.5 g = 0.0575 Kg
Initial speed of the ball: vbi = 26.7 m/s
Mass of the racket: M = 331 g = 0.331 Kg
Final speed of the ball: vbf = 29.5 m/s
A) We use the formula
pbin = m*vbi = 0.0575 Kg*26.7 m/s = 1.535 Kgm/s (+)
B) pbf = m*vbf = 0.0575 Kg*29.5 m/s = 1.696 Kgm/s (-)
C) We use the equation
Δp = pbf - pbin = 1.696 Kgm/s - (-1.535 Kgm/s) = 3.3925 Kgm/s
D) Knowing that
Δp = 3.3925 Kgm/s
we can say that
Δp = M*Δvr
⇒ Δvr = Δp / M
⇒ Δvr = 3.3925 Kgm/s / 0.331 Kg
⇒ Δvr = 10.249 m/s
The rate constant is 0.058/days and the population after 18 days is 412.38.
<h3>What is rate constant?</h3>
The rate constant of the population is calculated as follows;
N = N₀(2)^(rt)
where;
- r is the rate constant
- t of double of the population
when the population doubles, t = 12 days
2N₀ = N₀(2)^(12r)
2 = (2)^(12r)
ln(2) = 12r
r = ln(2)/12
r = 0.058/days
<h3>Population size after 18 days</h3>
The population size after 18 days is calculated as follows;
N = 200(2)^(0.058 x 18)
N = 412.38
Thus, the rate constant is 0.058/days and the population after 18 days is 412.38.
Learn more about rate constant here: brainly.com/question/11272059
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A 2-kg bowling ball sits on top of a building that is 40 meters tall.
GPE
A 2-kg bowling ball rolls at a speed of 5 m/s on the roof of the building that is 40 tall
its moving n its on top of a bldg. so ans is both KE n GPE
A 2-kg bowling ball rolls at a speed of 10 m/s on the ground.
KE
A 20-kg child is tossed up into the air by her parent. The child is 2 meters off the ground traveling 5 m/s.
moving n in the air. ans is both KE n GPE
eqn: KE= 1/2mv^2, GPE=hmg
A 1,000-kg car has 50,000 joules of kinetic energy. What is its speed?
50000=1/2*1000^v^2
v=10m/s
A 200-kg boulder has 39,200 joules of gravitational potential energy. What height is it at?
39200=200*9.8*h
h=20m
A 1-kg model airplane has 12.5 joules of kinetic energy and 98 joules of gravitational potential energy. What is its speed? What is its height?
12.5=1/2*1*v^2
v=5m/s
98=1*9.8*h
h=10m
Answer: It would destroy the Earth's surface.
I remember reading this questions in What If? by Randall Munroe. Great book, I suggest you check it out. Anyway, the answer. The Earth is revolving as well as spinning on its axis at the same time. This basically means that thee atmosphere is also spinning at the same speed. But due to the frame of reference, we don't notice anything. If the Earth suddenly stops spinning, then the atmosphere, going according to the first law of motion will still be spinning at the same speed. This would produce supersonic winds at such a scale that it will be compared to an atomic explosion. Anything not in a nuclear bunker will probably be ripped apart by the force of the wind.
Answer:
Option C - 39.2 J
Explanation:
We are given that;
Mass; m = 2 kg.
Distance moved off the floor;d = 10 m.
Acceleration due to gravity;g = 9.8 m/s².
We want to find the work done.
Now, the Formula for work done is given by;
Work = Force × displacement.
In this case, it's force of gravity to lift up the boots, thus;
Formula for this force is;
Force = mass x acceleration due to gravity
Force = 2 × 9.8 = 19.2 N
∴ Work done = 19.6 × 2
Work done = 39.2 J.
Hence, the Work done to life the boot of 2 kg to a height of 2 m is 39.2 J.