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Leya [2.2K]
2 years ago
13

A student calculates the density of a copper cube to be 4.15 g/cm . If the accepted value is 8.64 g/cm the percentage error in h

is
experimental value is
Physics
1 answer:
Helen [10]2 years ago
8 0

 The percentage error in his experimental value is -51.97%.

<h3>What is percentage error?</h3>

This is the ratio of the error to the actual measurement, expressed in percentage.

To calculate the percentage error of the student, we use the formula below.

Formula:

  • Error(%) = (calculated value-accepted value)100/(accepted............. Equation 1

From the question,

Given:

  • Calculated value = 4.15 g/cm
  • accepted value = 8.64 g/cm

Substitute these values into equation 1

  • Error(%) = (4.15-8.64)100/8.64
  • Error(%) = -4.49(100)/8.64
  • Error(%) = -449/8.64
  • Error(%) = -51.97 %

 

Hence, The percentage error in his experimental value is -51.97%.

Learn more percentage error here: brainly.com/question/5493941

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Gravitational potential energy is related to–A. what an object is made of. B.an object’s motion.C. an object’s position.D. an ob
Bas_tet [7]

Answer:

The Answer is B because the material the object is made of, the position, or the color have absolutely nothing to do with gravitational potential energy

7 0
2 years ago
Hello,Plz Help Which conditions are necessary for rain to form?
dimulka [17.4K]
Vas happenin!
The third one makes no since because the clouds carry the rain. It isn’t always cold when it’s going to rain

The fourth one is a good one

The second one again it’s not always cold when it’s raining

The first one could be it also

Hmmm I would go with the last one

Sorry if it’s wrong
5 0
3 years ago
Two similar sized stones one heavy and one light dropped from the same height into a pond explain why the impact of the heavy st
Zigmanuir [339]
In energy point of view, the larger stone had more potential energy before dropping. impacting the water, the larger one, having more kinetic energy which changed from potential energy, tranfered energy to the water and formed wave. the amplitude of the wave indicate the energy of the wave. more energy more amplitude.
5 0
3 years ago
ou are out stargazing with your 13.4-cm telescope. You point your telescope at an interesting formation in the sky, which you th
Alinara [238K]

Answer:

θ = 4.716 10⁻⁶ rad

Explanation:

In order for the releases to be considered separate, they must meet the Rayleigh criterion that establishes that the maximum diffraction of one star must coincide with the first minimum of the diffraction pattern of the second star.

We use the diffraction equation for a slit

            a sin θ = m λ

The minimum occurs at m = 1

             sin θ = λ / a

Since the angles in these systems are very small, we can approximate the sine to its angle in radians

             θ = λ / a

The telescope has a circular aperture whereby polar cords should be used, which introduces a constant number

           θ = 1.22 λ / a

Let's calculate

          θ = 1.22 518 10⁻⁹ / 13.4 10⁻²

          θ = 4.716 10⁻⁶ rad

8 0
3 years ago
If 3.61 m3 of a gas initially at STP is placed under a pressure of 2.67 atm , the temperature of the gas rises to 37.9 ∘C. What
Pavel [41]

Answer: 1.54m^3

Explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas at STP = 1 atm

P_2 = final pressure of gas = 2.67 atm

V_1 = initial volume of gas = 3.61m^3

V_2 = final volume of gas = ?

T_1 = initial temperature of gas at STP = 0^oC=273+0=273K

T_2 = final temperature of gas = 37.9^oC=273+37.9=310.9K

Now put all the given values in the above equation, we get:

\frac{1atm\times 3.61m^3}{273K}=\frac{2.67\times V_2}{310.9K}

V_2=1.54m^3

Thus the final volume will be 1.54m^3

7 0
3 years ago
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