An object ALWAYS has velocity, although the velocity may be zero for most of the time, or even all the time.
'Velocity' means the object's speed AND the direction in which it's moving.
As long as the girl stands and holds the ball in her hand, the ball's velocity is zero. As soon as she drops it out of her hand, it starts having velocity that's not zero.
While it's bouncing, its velocity is . . .
== growing and downward while it's falling from her hand toward the ground,
== zero for the instant of time when it hits the ground and changes direction from down to up,
== shrinking and upward while it's rising from the ground to her hand,
== zero for the instant of time when it hits her hand and changes direction from up to down.
F1x + F2x = Rx
↓
Rx = F1x + F2x
↓
Rx = F1 cos45° + F2
↓
Rx = (50N)(cos45°) + 60N
↓
Rx = 95N
Similarly, if we sum all the y components, we will get the y component of the resultant force:
F1y + F2y = Ry
↓
Ry = F1y + F2y
↓
Ry = F1 sin45° + 0
↓
Ry = F1 sin45°
↓
Ry = (50N)(sin45°)
↓
Ry = 35N
At this point, we know the x and y components of R, which we can use to find the magnitude and direction of R:
Rx = 95N
Ry = 35N
There are six distinct changes of phase which happens to different substances at different temperatures. ... Sublimation: the substance changes directly from a solid to a gas without going through the liquid phase. Deposition: the substance changes directly from a gas to a solid without going through the liquid phase.
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At r = 0.766 R the magnetic field intensity will be half of its value at the center of the current carrying loop.
We have a circular loop of radius ' r ' carrying current ' i '.
We have to find at what distance along the axis of the loop is the magnetic field one-half its value at the center of the loop.
<h3>What is the formula to calculate the
Magnetic field intensity due to a current carrying circular loop at a point on its axis?</h3>
The formula to calculate the magnetic field intensity due to a current carrying ( i ) circular loop of radius ' R ' at a distance ' x ' on its axis is given by -

Now, for magnetic field intensity at the center of the loop can calculated by putting x = 0 in the above equation. On solving, we get -

Let us assume that the distance at which the magnetic field intensity is one-half its value at the center of the loop be ' r '. Then -




r = 0.766R
Hence, at r = 0.766 R - the magnetic field intensity will be half of its value at the center of the current carrying loop.
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Answer:
Your weight is the combination of all the large-scale, long-term forces on your body. While the earth's gravity is by far the strongest large-scale force, it is not the only one. What you experience as "something pulling you down" is actually the total of all the forces and not just gravity. The four dominant large-scale,
Explanation: