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3 years ago

What's the balanced equation for Iron and copper (II) sulfate solution.

Chemistry

1 answer:

Georgia [21]3 years ago

5 0

Answer:

2Fe + 3CuSO₄ → Fe₂(SO₄)₃ + 3Cu

Explanation:

The reactants are:

Iron = Fe

Copper (II) sulfate solution = CuSO₄

The reaction is given as:

Fe + CuSO₄ → Fe₂(SO₄)₃ + Cu

This is a single displacement reaction;

Now let us balance the equation;

aFe + bCuSO₄ → cFe₂(SO₄)₃ + dCu

Conserving Fe;

a = 2c

Conserving Cu;

b = d

Conserving S;

b = 3c

Conserving O;

4b = 12c

let b = 1;

c = $\frac{1}{3}$

d = 1

a = $\frac{2}{3}$

Multiply through by 3 to get whole numbers;

a = 2, b = 3, c = 1 and d = 3

2Fe + 3CuSO₄ → Fe₂(SO₄)₃ + 3Cu

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Complete combustion of a compound containing hydrogen and carbon produced 2.641 g of carbon dioxide and 1.442 grams of water as

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The empirical formula of hydrocarbon is C₃H₈

The molecular formula of hydrocarbon is C₆H₁₆

Empirical formula calculation

Hydrocarbon contain carbon and hydrogen

Step 1: find the mass carbon (C) in carbon dioxide (CO₂) and hydrogen (H ) in water

mass of of element = molar mass of element/ molar mass molecule x total mass of molecule

From periodic table the molar mass of C =12, for CO₂ = 12+( 16 x2) =44 g/mol, for H = 1.00 g/mol, for H₂O = (2 x1)+16 = 18 g/mol

mass of C = 12/44 x 2.641 =0.7203 g

since there are 2 atom of H in H₂O the molar mass of H = 1 x2 = 2 g/mol

mass of H is therefore = 2/18 x 1.442 =0.1602 g

Step 2: find the moles of C and H

moles = mass÷ molar mass

moles of C = 0.7203 g÷ 12 g/mol = 0.060 moles

moles of H = 0.1602÷ 1 g/mol = 0.1602 moles

Step 3: find the mole ratio of C and H by dividing each mole by smallest mole ( 0.06)

for C = 0.06/0.06 =1

For H = 0.1602/0.06 =2.67

multiply by 3 to remove the decimal

For C = 1 x3 =3

For H = 2.67 x3 =8

therefore the empirical formula = C₃H₈

The molecular formula calculation

[C₃H₈]n = 88.1 g/mol

[12 x 3)+( 1 x8)]n =88.1 g/mol

44 n = 88.1

divide both side by 44

n=2

therefore [C₃H₈]₂ = C₆H₁₆

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