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iris [78.8K]
3 years ago
11

How does the average velocity of molecules in a high-temperature gas compare to the average velocity of molecules of the same ga

s with a lower temperature?
Chemistry
1 answer:
IrinaK [193]3 years ago
8 0

Answer:lower temp molecules act slower so they come closer together and heated molecules are more spaced out that is why when you put an ice cube in a hot pan the ice melts and turns into a liquid due to heat the molecules space out

Explanation:

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What is the relationship between a front and cloud formation?
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Cold air is more dense than warm air, so when a warm air mass meets a cold air mass, the cold air ends up below the warm air. Once the air has risen, it cools and clouds can form. Weather fronts can cause clouds to form.

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3 years ago
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PLEASE ANSWER WILL MARK BRAINLIST
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To find the experimental value I believe we add up all the temperatures found by each trial and divide by the number of trials

When added up and divided up this is 50.7 C

Then we continue with accepted value minus experimental value over accepted

53.0 - 50.7 / 53.0 x 100

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A type of erosion that occurs when large chunks of land or rock break away due to gravity.
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Calculate the volume in liters of 14.4 moles of neon gas at STP
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4 0
3 years ago
4720 kJ of energy are supplied to a material in order to raise its temperature by 65K. If the specific heat capacity of the mate
algol [13]

Answer : The correct answer for mass of material = 26.6 Kg

Given : Q = 4720 KJ

Change in Temperature ( ΔT ) = 65 K

Specific heat capacity of material ( c) = 2730 \frac{J}{Kg* K}

The relation between Q , ΔT , c and m are related by following formula :

Q = m* c*ΔT ,

where Q = Heat or energy absorbed or released

m = mass , c = specific heat ,ΔT = change in Temperature

Plugging value in heat formula :

4720 KJ = m * 2730 \frac{J}{Kg * K} * 65 K

4720 KJ = m * 177450 \frac{J}{Kg}

[[Converting 177450 \frac{J}{Kg}  to \frac{KJ}{Kg}

177450 \frac{J}{Kg}  * \frac{1 KJ}{1000 J}  = 177.450 \frac{KJ}{Kg} ]]

Dividing both side by 177.450 \frac{KJ}{Kg}

\frac{4720 KJ}{177.450 \frac{KJ}{Kg}}  = m * \frac{177.450\frac{KJ}{Kg} }{177.450\frac{KJ}{Kg} }

m = 26.6 Kg

6 0
3 years ago
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