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Ray Of Light [21]
3 years ago
13

A disk of radius R = 7.52 cm is centered at the origin and lies along the y – z plane. The disk has a surface charge density σ =

5.88 × 10 − 6 C / m 2 . Evaluate the electric field produced by this disk along the x axis at point (P = 1.01 m, 0.00 m). The Coulomb force constant k = 1 / ( 4 π ϵ 0 ) = 8.99 × 10 9 N ⋅ m 2 / C 2 .
Physics
1 answer:
mr Goodwill [35]3 years ago
5 0

Answer:

The electric field produced by this disk along the x axis at point (P = 1.01 m, 0.00 m) is 996.54 N/C

Explanation:

The electric field produced by this disk along the x axis at point (P = 1.01 m, 0.00 m), will be evaluated as follows:

Since x > 0

E_{x} = 2\pi \sigma k [1-\frac{x}{\sqrt{x^2 +R^2}}]

σ is surface charge density = 5.88 × 10⁻⁶ C / m²

R is the radius = 7.52cm = 0.0752m

position x = 1.01m

k is coulomb force constant = 8.99 × 10⁹ Nm² / C²

E_{x} = 2\pi ( 5.88X10^{-6})(8.99 X10^9)[1-\frac{1.01}{\sqrt{1.01^2 +0.0752^2}}]

    = 996.54 N/C

Therefore, The electric field produced by this disk along the x axis at point (P = 1.01 m, 0.00 m) is 996.54 N/C

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Answer:

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Explanation:

given data

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to find out

what is the volume of the bubble just before it reaches the surface

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we know at top atmospheric pressure is about P1 = 10^{5} Pa

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volume of the bubble just before it reaches the surface is 5.71 cm³

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