The asymmetric binding of citrate by the enzyme aconitase allows for asymmetric reactions of citrate in the citric acid cycle(TCA).
How does citrate behave during the TCA cycle?
Citrate synthase uses oxaloacetate and acetyl-CoA to create citrate in the Krebs cycle (CS). Citrate carrier allows for its export from the mitochondria (CIC). ACLY converts cytosolic citrate to acetyl-CoA and oxaloacetate. Fatty acid production can employ acetyl-CoA as a substrate.
What does the aconitase enzyme do?
Aconitase, also known as aconitate hydratase (EC 4.2.1.3), is an enzyme that catalyzes the non-redox-active process of stereo-specific conversion of citric acid(citrate) to isocitrate in the acid ( TCA ) cycle using cis-aconitate.
Therefore, option A is the correct choice.
Original question:
Citrate can react asymmetrically in the citric acid cycle because the enzyme aconitase
A) binds citrate asymmetrically.
B) binds either form of citrate.
C) binds both forms of isocitrate.
D) does not distinguish the -CH2COO- group.
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Answer:
Chi square value = 0.3
In order to find the expected value, an assumption of purple flower colour dominance over white flower colour has to be made.
Explanation:
<em>First, we will assume that the purple flower trait is dominant over white flower trait, and that the alleles segregate according to Mendelian standard. Hence, the expected F2 phenotypic ratio will be 3:1.</em>
In order to get the Chi square, the expected phenotype frequency will be calculated thus;
Expected frequency (E) for purple flowered plants = 3/4 x 160 = 120
Expected frequency (E) for white flowered plants = 1/4 x 160 = 40
Observed frequency (O) for purple flowered plants = 123
Observed frequency (O) for white flowered plants = 37
<em>Chi square 
= 
</em>
For the purple colour flower
, which gives 0.075
For the white colour flower
, which gives 0.225
<em>Total = 0.075 + 0.225, which gives 0.3</em>
The phase you should be viewing is the prophase
There are 3 Oxygen atoms bonded to 1 Nitrogen atom.
Hope this helps!
-Payshence
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