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Serhud [2]
3 years ago
15

Silver nitrate reacts with calcium chloride as

Chemistry
1 answer:
jarptica [38.1K]3 years ago
5 0

Answer:

11.8g of CaCl₂ would be required

Explanation:

To solve this question we need to find the moles of AgNO₃ in the solution. Thus, and using the chemical reaction we can find the moles of CaCl₂ required for a complete reaction and its mass as follows:

<em>Moles AgNO₃:</em>

420mL = 0.420L * (0.506mol / L) = 0.213 moles AgNO₃

<em>Moles CaCl₂:</em>

<em>Based on the chemical reaction, 2 moles of AgNO₃ react per mole of CaCl₂.</em>

The moles of CaCl₂ that will react are:

0.213 moles AgNO₃ * (1mol CaCl₂ / 2 mol AgNO₃) = 0.106 moles CaCl₂

<em>Mass CaCl₂ -Molar mass: 110.98g/mol-</em>

0.106 moles CaCl₂ * (110.98g / mol) =

<h3>11.8g of CaCl₂ would be required</h3>
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Explanation:

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