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brilliants [131]
3 years ago
9

At 25°c, what is the PH of a solution Prepared by dissolving 0.00465 mol of CA (Oh)2 in water to give 741.8mL of solution​

Chemistry
1 answer:
steposvetlana [31]3 years ago
7 0
The total ph is answer letter c
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The specific beta in aluminum is 0,900 J/g • Celsius. How much heat is required to raise the temperature of a 30.0 g block of al
maw [93]

Answer:

1350J

Explanation:

Heat energy = ?

Mass = 30.0g

Specific heat capacity (c) = 0.90J/g°C

Initial temperature (T1) = 25°C

Final temperature (T2) = 75°C

Heat energy (Q) = mc∇T

Q = heat energy

M = mass of the substance

C = specific heat capacity of the substance

∇T = change in temperature of the substance = T2 - T1

Q = mc∇T

Q = 30 × 0.90 × (75 - 25)

Q = 27 × 50

Q = 1350J

The heat energy required to raise the temperature of the metal from 25°C to 75°C is 1350J

5 0
3 years ago
An ___is usually a homologous structure that is shared by all organisms in a group~science
Paraphin [41]
A shared derived characteristics is usually a homologous structure, such as a backbone, that is shared by all organisms in a group.
8 0
3 years ago
Examining a corpse, you find many second instars and a few third instars on the body and moving away from it You find no pupae i
Bingel [31]

I don't know maybe 50 and 72 hours?

4 0
3 years ago
Read 2 more answers
How are atomic nuclei developed​
mezya [45]

Answer:

An atom is composed of a positively-charged nucleus, with a cloud of negatively-charged electrons surrounding it, bound together by electrostatic force. ... Protons and neutrons are bound together to form a nucleus by the nuclear force.

8 0
4 years ago
Calculate the heat released when 454 grams of steam at 100 degrees C condenses.
sasho [114]
<h3>Answer:</h3>

1026.05 kJ

<h3>Explanation:</h3>
  • The Quantity of heat is calculated by multiplying the mass of a substance by specific heat capacity and the change in temperature.
  • However, condensation takes place at a constant temperature.
  • Therefore, Quantity of heat is calculated by multiplying mass by the latent heat of vaporization.
  • That is; Q = m × Lv

In this case we are given;

Mass of steam as 454 g

To calculate the amount of heat released we must know the value of latent heat of vaporization;

The latent heat of vaporization of steam is 2260 J/g

Therefore;

Heat released, Q = 454 g × 2260 J/g

                             =1026040 Joules

But, 1000 joules = 1 kilo-joules

Thus, Q = 1026.04 kJ

Hence, the amount of heat released is 1026.05 kJ

5 0
3 years ago
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