Answer:
The correct answer is letter "B": Internal customers.
Explanation:
Internal customers are not necessarily employees or customers who work inside the organizations, but they usually do. These people have a certain relationship with the firm and one need from another so their jobs can be done. In the case of employees, they rely on others' roles so their responsibilities can be performed.
Answer: Mission
Explanation:
The organizational mission is one of the type of approach that is used for reflecting the various types of products and the services information and also it important values.
The main main objective of the organizational mission is that it helps in providing the various types of company statement based on its the organizational specific goals and the values.
According to the given question, the mission is one of the organizational factor that helps in value the employees and also respect their specific diversity.
Therefore, Mission is the correct answer.
Answer: $4680
Explanation:
The joint cost allocated to Preon will be calculated below as:
Preon's value will be:
= 14000 × $6.00
= $84000
Paron's value will be:
= 28000 × $2.00
= $56000
Total value = Preon's value + Paron's value
= $84000 + $56000
= $140000
The joint cost allocated to Preon will be
= 7800 × 84000/140000
= $4680
Answer:
a.
i. 4.7 times
ii. 77.1 days
b
i. 7 times
ii. 52.1 days
Explanation:
Inventory turnover = cost of goods sold / average inventory
average inventory for 2016 = ( 87,750 + 92,500 ) / 2 = $90,125
Inventory turnover $426,650 / $90,125 = 4.7 times
Days' sales in inventory = 365 / inventory turnover = 77.1 days
for 2017
inventory turnover = cost of goods sold / average inventory
average inventory for 2017 = ( 97,400 + 87,750 ) / 2 = $92,575
Inventory turnover $643,825 / $92,575 = 7.0 times
Days' sales in inventory = 365 / inventory turnover = 52.1 days
Answer:
0.2
Explanation:
The Probability distribution is the function which describes the likelihood of possible values assuming a random variable. The 10% of the items from the production line are assumed to be defective. There is a sample selection of 2 items. The probability that one of the item among the selected sample of two items is found defective is 0.2 (2 items sample *10%)
