The answer to this item is determined by using the proper conversion factors and the dimensional analysis. For the given units, meter and centimeters, the conversion from millimeters are as shown below,
1 m = 1000 mm
1 cm = 10 mm
Conversion of 5.3 mm³ to m³.
= (5.3 mm³)(1 m/1000 mm)³ = 5.3 x 10⁻⁹ m³
Conversion of 5.3 mm³ to cm³.
= (5.3 mm³)(1 cm/10 mm)³ = 5.3 x 10⁻³ cm³
The answer to this item is therefore letter B. 5.3 x 10⁻⁹ m³.
Partial/total moles= 0.5/2 & 1.5/2 it results to a ratio S:O where S=1 and O=3 the final answer will be SO3.. I hope that helped
Answer:
Explanation:
Henry's law states that the amount of dissolved gas in a liquid is proportional to its partial pressure above the liquid
number of moles of cyclopropane = 1.84 g / 42.08 g/mol = 0.044 mol
number of mole of water = 1010000 g / 18.02 g/mol = 56048.83 mol
mole fraction of cyclopropane = mole of cyclopropane / ( mole of water + mole of cyclopropane) = 0.044 mol / 56048.87 = 7.85 × 10⁻⁷
P cyclopropane = k henry × mole fraction of cyclopropane = 4273 atm × 7.85 × 10⁻⁷ = 0.00335 atm
b) number of cyclopropane molecules present in each cubic centimeter = ( 0.044 mol / 1010) × 6.022 × 10 ²³ / 1000 cm³ = 2.623 × 10 ¹⁶ molecules in cm³
Explanation:
If you look back at the formula ( SO2 ), you can see that there is one sulfur and two oxygens present. Therefore, the molar mass of sulfur dioxide is [1 × 32.1 + 2 × 16.0] = 64.1 g/mol.
