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dedylja [7]
3 years ago
15

Earlier in this lesson, you spent some time thinking about events that involve matter and energy. Consider balls of different sh

apes and materials that reach different heights as they bounce off the same floor. What aspect of this event relates to matter? What aspect relates to energy? Font Sizes
Physics
1 answer:
Marianna [84]3 years ago
5 0

Answer:

See the answer below

Explanation:

T<em>he aspect of the event that relates to matter is </em><em>the materials and different shapes of the balls</em><em> while the aspect that relates to energy is t</em><em>he heights reached by the balls as they bounce off the same floor.</em>

Matter is generally defined as any substance that has weight and is able to occupy space. <u>Hence, the balls being made up of different materials and shapes means that they are made up of matter. </u>

Energy, however, is generally defined as the capacity to do work. The more the energy of a system, the more the work that can be done by the system. <u>The height reached by the balls is thus an indication of the amount of energy possessed by the balls.</u>

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A 90 kg painter is standing on a horizontal wooden scaffolding of length 10 m, which is supported on each end by a rope. The pai
RSB [31]

Explanation:

For equilibrium, \sum M = 0.

So,   8 m \times mg - (10 m) T_{1} = 0

             T_{1} = \frac{8 \times mg}{10}

                        = \frac{8 \times 90 \times 9.8}{10}

                        = 705.6 N

Also, for equilibrium \sum F_{y} = 0

              T_{1} + T_{2} - mg = 0

or,         T_{2} = mg - T_{1}

                        = 90 \times 9.8 - 705.6

                        = 176.4 N

Thus, we can conclude that the tension in the first rope is 176.4 N.

8 0
4 years ago
Two blocks of masses m and M are connected by a string and pass over a frictionless pulley. Mass m hangs vertically, and mass M
horsena [70]

Answer:

sin\theta - \mu_k cos\theta = \frac{m}{M}

sin\theta - \mu_k cos\theta = 1

Explanation:

Force of friction on M mass so that it will move down the inclined plane is given as

F_f = \mu Mgcos\theta

now if it is moving down the inclined plane at constant speed

so we will have

Mgsin\theta - T - \mu mgcos\theta = 0

on other side the mass "m" will go up at constant speed

so we have

T - mg = 0

so we have

Mgsin\theta = \mu Mgcos\theta + mg

so we have

sin\theta - \mu_k cos\theta = \frac{m}{M}

for special case when m = M

then we have

sin\theta - \mu_k cos\theta = 1

5 0
3 years ago
How much time will it take for a truck to travel 20 meters if it is traveling at 4 m/s?
ss7ja [257]

Answer:

<h2>The answer is 5 s</h2>

Explanation:

The time taken can be found by using the formula

t =  \frac{d}{v}  \\

d is the distance

v is the velocity

From the question we have

t =  \frac{20}{4}  \\

We have the final answer as

<h3>5 s</h3>

Hope this helps you

4 0
3 years ago
Read 2 more answers
If the wagon travels 18.75 m, what is the work done on the wagon
Schach [20]

If the wagon travels 18.75 m, then the work done on the wagon is

(18.75 m) x (the steady force applied to the wagon all the way, in Newtons) .

The unit is Joules .


4 0
3 years ago
A box falls out of a stationary helicopter hovering 135 m above the ground. How long will it take to hit the ground?
Marrrta [24]

We have the equation of motion s = ut + \frac{1}{2} at^2, where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.

Here displacement = 135 m, Initial velocity = 0 m/s, acceleration = 9.81 m/s^2

Substituting

   135 = 0*t+\frac{1}{2} *9.8*t^2\\ \\ 4.9t^2 =135\\ \\ t =5.25 seconds

A box falls out of a stationary helicopter hovering 135 m above the ground will take 5.25 seconds to reach the ground.

4 0
3 years ago
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