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2 years ago

Why it is easier to remove a 2p electron from an oxygen atom than from a nitrogen atom?

Physics

1 answer:

DedPeter [7]2 years ago

7 0

Answer:

The electrons in oxygen are paired while in nitrogen, they are not.

Explanation:

To analyse this we start with writing out the ground state electronic configurations for both elements.

Oxygen: 1s²2s²2p4 meaning the p subshell has the following arrangement of electrons ↑↓ ↑ ↑

Nitrogen : 1s²2s²2p³ meaning the p subshell has the following arrangement of electrons ↑ ↑ ↑

Clearly the paired electron in oxygen will be experiencing repulsion from the electron it shares an orbital with causing it to be removed easily. The electrons in nitrogen are unpaired, each orbital is singly occupied

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The term used to describe the quantity of matter that a body possesses is:

barxatty [35]

The term used to describe the quantity of matter that a body possesses is mass.

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3 years ago

An argon ion laser puts out 5.0 W of continuous power at a wavelength of 532 nm. The diameter of the laser beam is 5.5 mm. If th

stepan [7]

Answer:

Number of photons travel through pin hole= $6.4*10^{17}$

Explanation:

First we will calculate the energy of single photon using below formula:

$E=\frac{h*c}{λ}$

Where :

h is plank's constant with value $6.626*10^{-34} J.s$

c is the speed of light whch is $3*10^{8}$

λ is the wave length = 532nm

$E=\frac{6.6268*10^{-34}* 3*10^{8}}{532nm}$

E= $3.73*10^{-19}$ J

Number of photons emitted per second:

$\frac{5J/s}{1 photon/3.73*10^{-19} }$

Number of photons emitted per second= $1.34*10^{19} photons/s$

$\frac{A-hole}{A-beam}$ = $\frac{\frac{pie*d-hole^2}{4}}{\frac{pie*d-beam^2}{4} }$

Where:

A-hole is area of hole

A-beam is area of beam

d-hole is diameter of hole

d-beam is diameter if beam

$\frac{A-hole}{A-beam}$ = $\frac{d-hole^2}{d-beam^2}$

$\frac{Ahole}{A-beam}$ = $\frac{1.22^2}{5.5^2}$

$\frac{A-hole}{A-beam}$ = $\frac{144}{3025}$

Number of photons travel through pin hole= $1.34*10^{19} *\frac{144}{3025}$

Number of photons travel through pin hole= $6.4*10^{17}$

7 0

3 years ago

A car, travelling at constant speed on a straight, level road, accelerates so that its speed is now doubled. By what factor will

Anettt [7]

Answer:

We know that, the kinetic energy

ke= \frac{1 }{2} m{v}^{2}

and we also know that the acceleration causes the speed's value to be doubled

Hence, v becomes 2v

When 2v is squared, it becomes 4v^2. After substituting this value in the equation above and comparing it,

We can conclude that the Kinetic Energy has increased

by a factor of 4

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3 years ago

Un auto parte desde un lugar a las 6:00 de la mañana con una rapidez de 150 Km/hr a través de una carretera recta. a) ¿Qué dista

Gwar [14]

Answer:

600 km

6 hours

Explanation:

El tiempo que viaja el automóvil de 6 a 10 de la mañana es $10-6=4\ \text{horas}$

La velocidad del coche es 150 km/hr

La distancia está dada por

$\text{Distancia}=\text{Velocidad}\times \text{Tiempo}$

$150\times 4=600\ \text{km}$

A distancia recorrida a las 10 de la mañana es de 600 km.

Ahora el tiempo que se toma está dado por

$\text{Tiempo}=\dfrac{\text{Distancia}}{\text{Velocidad}}$

$\dfrac{900}{150}=6\ \text{horas}$

El tiempo que se tarda en recorrer 900 km es de 6 horas.

8 0

3 years ago

Why does electrical current always flow from areas of negative charge to areas of positive charge?

dexar [7]

<span>Negative is attracted to positive. </span>

3 0

3 years ago

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