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serious [3.7K]
3 years ago
14

2. You are on your skateboard doing 2.4 m/s when you start to accelerate at 0.6 m/s down a hill for 20.5. How fard

Physics
1 answer:
Maksim231197 [3]3 years ago
4 0

Answer:

175 m

Explanation:

Given:

v₀ = 2.4 m/s

a = 0.6 m/s²

t = 20.5 s

Unknown:

Δx

Equation:

Δx = v₀ t + ½ at²

Sub and solve:

Δx = (2.4 m/s) (20.5 s) + ½ (0.6 m/s²) (20.5 s)²

Δx ≈ 175 m

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An object is 39 cm away from a concave mirrors surface along the principles axis. If the mirrors focal length is 9.50 cm, how fa
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Answer:

12.6 cm

Explanation:

We can use the mirror equation to find the distance of the image from the mirror:

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}

where here we have

f = 9.50 cm is the focal length

p = 39 cm is the distance of the object from the mirror

Solving the equation for q, we find:

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{9.50 cm}-\frac{1}{39 cm}=0.080 cm^{-1}\\q = \frac{1}{0.080 cm}=12.6 cm

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3 years ago
How many satellites are used for GPS ?
noname [10]
Around 27 satelites is used for GPS technology
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3 years ago
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What is the name of the chart that contain elements?​
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Answer:

Element Chart

Explanation:

It is a chart that provides many different elements.

7 0
3 years ago
Six baseball throws are shown below. In each case the baseball is thrown at the same initial speed and from the same height h ab
Assoli18 [71]

Answer:

EXplained

Explanation:

from conservation of energy

change in potential energy = gain in kinetic energy

so as all he balls are throws from the same height thus the change in potential energy is the same for all the balls thus the gain in kinetic energy is the same for all the balls and as they have the same initial velocity thus the final velocity is the same for all the balls.

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calculate the work done in kilo joules in lifting a mass of 20kg at steady velocity through a vertical height of 20m
bulgar [2K]

Answer:

\huge\boxed{\sf Work\ done = 4 kJ}

Explanation:

Since work done is in the form of potential energy, we will use the formula of potential energy here.

We know that,

<h3>P.E. = mgh </h3>

Where,

m = mass = 20 kg

g = acceleration due to gravity = 10 m/s²

h = vertical height = 20 m

So,

<h3>Work done = mgh</h3>

Work done = (20)(10)(20)

Work done = 4000 joules

Work done = 4 kJ

\rule[225]{225}{2}

5 0
2 years ago
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