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3 years ago

2. You are on your skateboard doing 2.4 m/s when you start to accelerate at 0.6 m/s down a hill for 20.5. How fard

Physics

1 answer:

Maksim231197 [3]3 years ago

4 0

Answer:

175 m

Explanation:

Given:

v₀ = 2.4 m/s

a = 0.6 m/s²

t = 20.5 s

Unknown:

Δx

Equation:

Δx = v₀ t + ½ at²

Sub and solve:

Δx = (2.4 m/s) (20.5 s) + ½ (0.6 m/s²) (20.5 s)²

Δx ≈ 175 m

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anyanavicka [17]

Answer:

The answer to your question is 5.4 cm

Explanation:

This problem refers to calculate the change in length in one dimension due to a change in temperature.

Data

α = 12 x 10⁻⁶

Lo = 150 meters

ΔT = 30 °C

Formula

ΔL/Lo = αΔT

solve for ΔL

ΔL = αLoΔT

Substitution

ΔL = (12 x 10⁻⁶)(150)(30)

Simplification

ΔL = 0054 m = 5.4 cm

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3 years ago

An electron with a speed of 0.95c is emitted by a supernova, where cc is the speed of light. What is the magnitude of the moment

krok68 [10]

Answer:

2.59×10¯²² Kgm/s

Explanation:

Data obtained from the question include:

Velocity of electron = 0.95c

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Next, we shall determine the velocity of the electron. This can be obtained as follow:

Velocity of electron = 0.95c

Velocity of Light (c) = 3×10⁸ m/s

Velocity of electron = 0.95c

Velocity of electron = 0.95 × 3×10⁸

Velocity of electron = 2.85×10⁸ m/s

Finally, we shall determine the mometum of the electron.

Momentum is simply defined as the product of mass and velocity. Mathematically, it is expressed as:

Momentum = mass x Velocity

Thus, with the above formula, we calculate the momentum of the electron as follow:

Mass of electron = 9.1×10¯³¹ Kg

Velocity of electron = 2.85×10⁸ m/s

Momentum of electron =?

Momentum = mass x Velocity

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Momentum = 2.59×10¯²² Kgm/s

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3 years ago

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den301095 [7]

Answer:

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Let the maximum height reached be h.

Here initial velocity, u = 5 m/s

Final velocity, V = 0

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V^2 = u^2 + 2 g h

0 = 25 - 2 × 9.8 × h

h = 25/19.6 = 1.275 m

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3 years ago

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find the mass of a ball on a roof 30 meters high, if the ball's gravitational potential energy is 58.8 joules

Sidana [21]

We are given the gravitational potential energy and the height of the ball and is asked in the problem to determine the mass of the ball. the formula to be followed is PE = mgh where g is the gravitational acceleration equal to 9.81 m/s^2. substituting, 58.8 J = m*9.8 m/s^2 * 30 m; m = 0.2 kg.

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3 years ago

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Sloan [31]

Answer:

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Explanation:

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