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ioda
3 years ago
12

An atom has three shells with 3 electrons in the last shell. This atom could be.....

Chemistry
1 answer:
Oksana_A [137]3 years ago
4 0
Since the total amount of valence electrons is 3, it is in group 13 in the periodic table..therefore, it is specified as Boron.✅
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Which of these force is reponsible for attracting the opposite poles of two bar magments towards each other
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The magnetic fields are the reason  why magnets repel and attract. eachother. 
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Arsenic produces a blue flame when heated. Calcium produces an orange-red flame. Which of these best explains why this differenc
MrMuchimi

Flame colors are produced from the movement of the electrons in the metal ions present in the compounds. When you heat it, the electrons gain energy and can jump into any of the empty orbitals at higher levels Each of these jumps involves a specific amount of energy being released as light energy, and each corresponds to a particular color. As a result of all these jumps, a spectrum of colored lines will be produced. The color you see will be a combination of all these individual colors.

6 0
3 years ago
An air compressor takes atmospheric air (think about what pressure it is at) and pressures it up to 68 (psig). In the process, i
Aleks [24]

Answer:

5.19 m³  

Explanation:

Data Given:

initial Pressure P1 = atmospheric pressure

Reported atmospheric pressure =  14.696 psi

Final pressures P2 =  68 psi

initial Temperature T1 =  26 °C

final Temperature T2 =  48 °C

initial Volume V1= 13 m³

final Volume V2 = ?

Solution:

Formula will be used

                    P1 V1 / T1 = P2 V2 / T2

To calculate volume rearrange the above formula

                   V2 = (P1 V1) T2 / T1 P2 . . . . . . . .(1)

put values in equation 1

                  V2 = (14.696 psi x 13 m³) 48 °C / 26 °C x 68 psi

                  V2 = (191.05 psi m³) 48 °C / 1768 °C psi

                  V2 = (9170.3  psi m³ °C / 1768 °C psi

                  V2 = 5.19 m³

So, final volume is 5.19 m³                

7 0
3 years ago
A crystallographer measures the horizontal spacing between molecules in a crystal. The spacing is
liubo4ka [24]
The spacing is 14.4 nm (nanometers).
It is 14.4 * 10^(-9) m
And 1 mm = 1 * 10^(-3) m
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Or : 1.512 * 10^(-3) mm
Answer: The total width of crystal is 0.001512 mm.
3 0
3 years ago
g compute the specific heat capacity at constant volume of nitrogen gas. the molar mass of N2 is 29.0 You warm 1.8 kg ov water a
Elis [28]

Complete question:

(a) compute the specific heat capacity at constant volume of nitrogen gas. the molar mass of N₂ is 29.0 You warm 1.8 kg of water at a constant volume 1.00 L from  21 C to 30.5 C in a kettle. For the same amount of heat, how many kilograms of 21∘C air would you be able to warm to 30.5∘C ?

(b) What volume (in liters) would this air occupy at 21∘C and a pressure of 1.00 atm? Make the simplifying assumption that air is 100% N₂​

Answer:

(a) The specific heat capacity of N₂ is 715.86 J/kg.K

(b) The volume the air occupy at 21∘C is 8784.29 Liters

Explanation:

Given;

M is the molar mass of N₂ = 29 x 10⁻³ kg/mol

specific heat of N₂ at constant volume, Cv = 20.76 J/mol.K

(a)

The specific heat capacity of N₂ is calculated as;

C = \frac{C_v}{M} \\\\C = \frac{20.76}{29 *10^{-3}} \\\\C = 715.86  \ J/kg.K

(b) heat capacity of water;

Q = mcΔθ

where;

c is the specific heat capacity of water = 4200 J/kg.K

m is mass of water, = 1.8 kg

Δθ is change in temperature, = 30.5 - 21 = 9.5 °C

Q = 1.8 x 4200 x  9.5

Q = 71820 J

Mass of nitrogen gas N₂, at this quantity of heat;

m_{N_2} = \frac{Q}{C*\delta \theta} \\\\m_{N_2} = \frac{71820}{715.86*9.5}\\\\m_{N_2} = 10.56 \ kg

The volume this air occupy at 21∘C

Apply ideal gas law;

PV = nRT = \frac{m}{M} RT

PV = \frac{mRT}{M} \\\\V = \frac{mRT}{MP}\\\\V = \frac{10.56(kg)*8.314*10^3(L.Pa/mol.K)*294(K)}{29*10^{-3}(kg)1.01325*10^5 (Pa)}\\\\V = 8784.29 \ Liters

6 0
3 years ago
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