All categories

3 years ago

Question 3 (Molarity)

Chemistry

1 answer:

antiseptic1488 [7]3 years ago

8 0

Answer:

The molarity of the solution is 1,03 M.

Explanation:

Molarity is a concentration measure that expresses the moles of solute (in this case HBR) in 1 liter of solution (1000ml). First we calculate the mass of 1 mol of HBr, to calculate the moles that are in 50 g of said compound:

Weight 1 mol HBr= Weight H + Weight Br= 1,01g + 79,90g= 80, 91 g/mol

80,91 g ----1 mol HBr

50,0 g------x= (50,0 g x1 mol HBr)/80,91 g= 0,62 mol HBr

600 ml solution-----0,62 mol HBr

1000ml solution------x= (1000ml solution x 0,62 mol HBr)/600 ml solution

x=1,03 moles HBr ---> The solution is 1,03M

You might be interested in

Given each pair, complete the sentences to determine which member of each has the stronger intermolecular dispersion forces.

evablogger [386]

Answer:

CH3CH2CH2Cl

CH3CH2CH2CH2CH2SH

Br2

Explanation:

Dispersion forces increases with increase in relative molecular mass. The specie having the greater relative molecular mass definitely has greater dispersion forces. A rough estimation of the relative molecular masses of the species stated in the answer will reveal this fact.

3 0

3 years ago

When air pressure rapidly falls, what weather change usually occurs?

Mama L [17]

hope this helps

Explanation:

a prolong storm will occur

that's what I found

8 0

3 years ago

The proper disposal of waste materials is covered under osha 1926.252 in

patriot [66]

1962.252(a) whenever the material is dropped from 20feet to any poiny lying outside the exterior wall of building, an enclosed chute of wood, or equivalent material. For the purpose of paragraph, an enclose chute is a slide, closed in all sides, through which material is placed from high plac eto lower one. 1962.252(b) when the disposal is dropped through holes in the floor without the use of chute, the area onto which the material is dropped shall be completely enclosed with barricades not less than 42 inch high and not less than 6 feet back from the projected edge of of the opening valve. signs warning of hazards of falling material shall be posted at each level. 1962.252(c) All scrap lumper, waste material, and rubbish shall be removed from the immediate work area as the work progresses. 1962.252(d) Disposal of waste material or debris by burning shall comply with local fire regulation 1962.252(e) All sovent waste, oily rags, and flammable liquid should be kept in fire resistant covered container until removed from work site.

8 0

3 years ago

An aircraft is taking a group of skydivers up into the air. Evan is dressed in

meriva

4,410 kJ

Explanation:

Gravitational Potential Enegry (GPE) is calculated as;

GPE = m*g*h where;

m = mass (kg)

g = gravity (m/s²)

h = height (meters)

= 90 * 9.8 * 5000

= 4,410,000‬ joules

= 4,410 kJ

7 0

3 years ago

CO(g)+2H2(g)⇌CH3OH(g) A reaction mixture in a 5.23-L flask at a certain temperature initially contains 27.2 g CO and 2.36 g H2.

irga5000 [103]

Answer: 5.70M

Explanation:

Molar mass of CO = 28.01 g/mol

Molar mass of H2 = 2.02 g/mol

Molar mass of CH3OH = 32.05 g/mol.

To determine the amount of each compound in the reaction mixture we use the formula.

Amount in mol = reacting mass/molar mass.

Inputing the given values we have,

26.6 g CO x (1 mol / 28.01 g ) = 0.9496608354 mol of CO.

To calculate the concentration of CO we use C=n/v, where n=amount and v= volume of CO.

Inputing the values in the formula

[CO] = 0.9496608354 mol CO / 5.23 L = 0.18158 M CO

Repeating thesame procedure for H

Amount of H=2.36 g H2 x ( 1 mol / 2.02 g ) = 1.168316832 mol of H2

Concentration of H2 in the mixture

[H2] = 1.168316832 mol H2 / 5.23 L = 0.223388 M of H2

Amount of CH3OH is determine similarly using rmass/molar mass

8.66 CH3OH x (1 mol / 32.05 g ) = 0.2702028081 mol of CH3OH

Concentration of

[CH3OH] = 0.2702028081 mol CH3OH/ 5.23 L = 0.051664 M CH3OH

Now equilibrium constant is determined by

Kc = [CH3OH] / [CO] [H2]^2

=0.051664/0.18158×0.223388×0.223388.

=5.70

7 0

3 years ago