To solve this problem it is necessary to apply the concepts related to energy conservation. Therefore, the work done will initially be equivalent to the change in kinematic energy. And this kinematic energy will be equivalent to the sum of energy (work) carried out by force and friction. In this way we have to
Now,
For each one we have
Then at the equation of equilibrium of energy we have,
Therefore the work done by friction on the chair is -833.7J
Answer:
h = 12.6 cm
Explanation:
given,
ground reaction = 788 N
time of force application = 0.9 s
BW = 670 N
Net force = 788 - 670
= 118 N
impulse = F x t
I = 118 x 0.9
I = 107.1 N s
impulse is equal to change in momentum
v = 1.57 m/s
v is the initial velocity before jump
now, height of center of mass
using equation of motion
v² = u² - 2 g h
h = 0.1257 m
h = 12.6 cm
the height of center of mass is equal to h = 0.126 m or 12.6 cm
Answer:
V= 150
Explanation:
9000/60 or 9000 ÷ 60 is 150
The formula is displacement divided by change of time.
Answer: A part of the incident light may get reflected or scattered, as it passes through the interior of the material. Any object, seen through a translucent material, appears fuzzy or blurred. Some examples are oily paper, tissue, some plastics, etc. [Image will be Uploaded Soon]
Explanation:
It is due to the excess stress.