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3 years ago

Maureen is training for a backpacking trip. Which of the following training plans follows the FITT

Physics

1 answer:

lawyer [7]3 years ago

6 0

Answer:

The answer is "Walk three days a week, gradually adding distance and hills."

Explanation:

The FITT Principle guides a person in becoming a fitter version of himself by following a particular frequency, intensity, time and type of exercise in order to achieve his goals.

Frequency- this refers to how often a person should do an exercise. For example, 5 times a week of intense core workout.

Intensity- this refers to the person's vigour or strength in doing the workout. This depends whether the person is doing a high-intensity or a low-intensity exercise.

Time- this refers to the length of a person's exercise. This will largely depend on every individual's fitness level.

Type of Exercise- this refers to the exercise that a person should incorporate in his training in order to avoid injuries of using the same muscles over and over again.

Among the choices above, it is only the second choice (Walk three days a week, gradually adding distance and hills) that follows the FITT principle. Walking shouldn't be kept at the same pace and distance for many weeks, since it results to boredom and overuse injuries. This will also lead to a plateau when it comes to people who are trying to lose weight because the body has already well-adjusted to the exercise and cannot be challenged anymore.

Gradually increasing the distance and hills will allow the person to be more challenged and will also increase his desire to workout (because he is seeing results).

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in a solar system far, far away the sun's intensity is 200 w/m2 for an inner planet located a distance r away. what is the sun's

GarryVolchara [31]

The sun's intensity for an outer planet located at a distance 6r from the sun is 5.55 W/m². The result is obtained by using the inverse square law formula.

<h3>What is the Inverse Square Law formula?</h3>

The Inverse Square Law formula describes the intensity of light is inversely proportional to the square of the distance. It can be expressed as

$\frac{I_{1} }{I_{2} } = \frac{d_{2}^{2} }{d_{1}^{2}}$

Where

I₁ = Intensity at distance 1 (W/m²)
I₂ = Intensity at distance 2 (W/m²)
d₁ = distance 1 from a light source (m)
d₂ = distance 2 from a light source (m)

Given the case the sun's intensity is 200 W/m² for an inner planet at the distance r. If an outer planet is at a distance 6r, what is the sun's intensity?

By using the inverse square law formula, the sun's intensity for an outer planet is

$\frac{I_{1} }{I_{2} } = \frac{d_{2}^{2} }{d_{1}^{2}}$

$\frac{200 }{I_{2} } = \frac{(6r)^{2} }{r^{2}}$

$\frac{200 }{I_{2} } = \frac{36r^{2} }{r^{2}}$

$I_{2} = \frac{200} {36}$

I₂ = 5.55 W/m²

Hence, the sun's intensity for a planet at a distance 6r from the sun is 5.55 W/m².

Learn more about intensity of light here:

brainly.com/question/13155277

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1 year ago

An acorn falls 10 meters in 4 seconds. What is its average velocity?

quester [9]

Answer:

Average velocity, V = 2.5m/s

Explanation:

Given the following data

Displacement = 10m

Time = 4secs

Average velocity can be defined as the rate of change in displacement with time. Velocity is a vector quantity and as such it has both magnitude and direction.

Mathematically, average velocity is given by the equation;

$Velocity = \frac{displacement}{time}$