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3 years ago

Maureen is training for a backpacking trip. Which of the following training plans follows the FITT

Physics

1 answer:

lawyer [7]3 years ago

6 0

Answer:

The answer is "Walk three days a week, gradually adding distance and hills."

Explanation:

The FITT Principle guides a person in becoming a fitter version of himself by following a particular frequency, intensity, time and type of exercise in order to achieve his goals.

Frequency- this refers to how often a person should do an exercise. For example, 5 times a week of intense core workout.

Intensity- this refers to the person's vigour or strength in doing the workout. This depends whether the person is doing a high-intensity or a low-intensity exercise.

Time- this refers to the length of a person's exercise. This will largely depend on every individual's fitness level.

Type of Exercise- this refers to the exercise that a person should incorporate in his training in order to avoid injuries of using the same muscles over and over again.

Among the choices above, it is only the second choice (Walk three days a week, gradually adding distance and hills) that follows the FITT principle. Walking shouldn't be kept at the same pace and distance for many weeks, since it results to boredom and overuse injuries. This will also lead to a plateau when it comes to people who are trying to lose weight because the body has already well-adjusted to the exercise and cannot be challenged anymore.

Gradually increasing the distance and hills will allow the person to be more challenged and will also increase his desire to workout (because he is seeing results).

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A sphere moves in simple harmonic motion with a frequency of 4.80 Hz and an amplitude of 3.40 cm. (a) Through what total distanc

geniusboy [140]

Answer:

a) the total distance traveled by the sphere during one cycle of its motion = 13.60 cm

b) The maximum speed is = 102.54 cm/s

The maximum speed occurs at maximum excursion from equilibrium.

c) The maximum magnitude of the acceleration of the sphere is = 30.93 $m/s^2$

The maximum acceleration occurs at maximum excursion from equilibrium.

Explanation:

Given that :

Frequency (f) = 4.80 Hz

Amplitude (A) = 3.40 cm

The total distance traveled by the sphere during one cycle of simple harmonic motion is:

d = 4A (where A is the Amplitude)

d = 4(3.40 cm)

d = 13.60 cm

Hence, the total distance traveled by the sphere during one cycle of its motion = 13.60 cm

As we all know that:

$x = Asin \omega t$

Differentiating the above expression with respect to x ; we have :

$\frac{d}{dt}(x) = \frac{d}{dt}(Asin \omega t)$

$v = A \omega cos \omega t$

Assuming the maximum value of the speed(v) takes place when cosine function is maximum and the maximum value for cosine function is 1 ;

Then:

$v_{max} = A \omega$

We can then say that the maximum speed therefore occurs at the mean (excursion) position where ; x = 0 i.e at maximum excursion from equilibrium

substituting $2 \pi f$ for $\omega$ in the above expression;

$v_{max} = A(2 \pi f)$

$v_{max} = 3.40 cm (2 \pi *4.80)$

$v_{max} = 102.54 \ cm/s$

Therefore, the maximum speed is = 102.54 cm/s

The maximum speed occurs at maximum excursion from equilibrium.

c) Again;

$v = A \omega cos \omega t$

By differentiation with respect to t;

$\frac{d}{dt}(v) = \frac{d}{dt}(A \omega cos \omega t)$

$a =- A \omega^2 sin \omega t$

The maximum acceleration of the sphere is;

$a_{max} =A \omega^2$

where;

$w = 2 \pi f$

$a_{max} = A(2 \pi f)^2$

where A= 3.40 cm = 0.034 m

$a_{max} = 0.034*(2 \pi *4.80)^2$

$a_{max} = 30.93 \ m/s^2$

The maximum magnitude of the acceleration of the sphere is = 30.93 $m/s^2$

The maximum acceleration occurs at maximum excursion from equilibrium where the oscillating sphere will have maximum acceleration at the turning points when the sphere has maximum displacement of $x = \pm A$

6 0

3 years ago

Name an object with the same diameter or a distance equal to the diameter of a crater on Halley’s nucleus.

natka813 [3]

Answer:

Asteroids:

Explanation:

Asteroids are rocky, airless worlds that orbit our sun, but are too small to be called planets. Tens of thousands of these minor planets are gathered in the main asteroid belt, a vast doughnut-shaped ring between the orbits of Mars and Jupiter. Asteroids that pass close to Earth are called near-earth objects.

3 0

3 years ago

A 0.060 kg ball hits the ground with a speed of –32 m/s. The ball is in contact with the ground for 45 milliseconds and the grou

SCORPION-xisa [38]

Answer:

imma try and get it wrong

3 0

3 years ago

In his explanation of the threshold frequency in the photoelectric field, Einstein reasoned that the absorbed photon must have t

Doss [256]

Answer:

4.6×10^-7 m or 0.46nm

Explanation:

From

Wo= hc/λ

Where:

Wo= work function of the metal

h= planks constant

c= speed of light

λ= wavelength

λ= hc/Wo

λ= 6.6×10^-34 × 3×10^8/4.30×10^-19

λ= 4.6×10^-7 m

5 0

3 years ago

In music, the note G above middle C has a frequency of about 392 hertz. If the speed of sound in the air is 340 m/s, what is the

morpeh [17]

Answer:

0.87 meters

Explanation:

7 0

3 years ago