Aerobic respiration is the process in which

ATP is a source of free energy that drives unfavorable reactions. Which of the processes are coupled to the dephosphorylation of

EleoNora [17]

Answer:

The correct statements are a denovo anabolism of nucleotides d myosin action during muscle contraction e membrane transport that maintain levels in the cell.

Explanation:

ATP or adenosine tri phosphate is an high energy compound.The hydrolysis of ATP helps to drive many thermo dynamically unfavorable reaction.The processes which are coupled to the de phosphorylation of ATP are given below.

1 De novo synthesis of nucleotides that requires energy in form of ATP.

2 During muscle contraction the sliding of thick filaments or myosin over thin filament or actin requires energy derived from the hydrolysis of ATP.

3 Membrane transport basically active transport helps in the uphill transport of ions that requires free energy in form of ATP.

3 0

3 years ago

PLEASE HELP!!

lana66690 [7]

Answer:

c

Explanation:

3 0

4 years ago

Read 2 more answers

PCL was mixed with gelatin to make a blend for elctrospun fibrous scaffold encapsulating growth factor that was admixed in the p

shusha [124]

Answer:

Explanation:

First PCL to form a scaffold, combined with gelatin.

They are made by first three forms A) made by just PCL.B) made by gelatin ratio PCL is 3:1 and last is C) made by gelatin PCL.

The decoration rate is 1%, 25% and 50% respectively.

A) Growth factor is stuck in 21 days, and can not spread. In this case in vivo experiment for 7 days used highly degradable scaffold use the ability to break down due to decomposition in vivo degradation rate depends on the scaffold's acid byproduct impact.

B) the amount of scaffolded degradation.

First, with scaffold A.

10 mg scaffold weight A= 1 per cent degradation.

Following degradation wt is 9.967=? Degradation per cent.

So, degradation (9.967* 1)/10= 0.9967 per cent.

Likewise for C) scaffold c 10 mg wt. Loss of 50 per cent.

After wt 8.33=? Degradation per cent.

Degradation (8.33* 50)/10=41.65 per cent.

Scaffold c degrades significantly, since the loss of wt is even greater.

7 0

4 years ago

52.1 mL of aqueous 0.255 M Pb(NO3)2 is mixed with 38.5 mL of 0.415 M NaCl. The equation for the precipitate reaction is: Pb(NO3)

Elan Coil [88]

Answer:

0.0585 M

Explanation:

Pb(NO₃)₂ (aq) + 2NaCl (aq) → PbCl₂ (s) + 2NaNO₃ (aq)

First we calculate the inital number of moles of each reagent, using the given volumes and concentrations:

0.255 M Pb(NO₃)₂ * 52.1 mL = 13.3 mmol Pb(NO₃)₂

0.415 M NaCl * 38.5 mL = 16.0 mmol NaCl

Then we calculate how many Pb(NO₃)₂ moles reacted with 16.0 mmoles of NaCl, using the stoichiometric coefficients of the reaction:

16.0 mmol NaCl * $\frac{1mmolPb(NO_3)_2}{2mmolNaCl}$ = 8.00 mmol Pb(NO₃)₂

Now we calculate the remaining number of Pb(NO₃)₂ moles after the reaction:

13.3 mmol - 8.00 mmol = 5.30 mmol Pb(NO₃)₂

Finally we divide the number of moles by the final volume to calculate the concentration:

5.30 mmol / (52.1 mL + 38.5 mL) = 0.0585 M

6 0

3 years ago

An oven heats up and the whole kitchen becomes warm because of heat transfer by

Ad libitum [116K]

B, it's properly because of convection! Please, correct me if I'm wrong :>

6 0

3 years ago