Answer:
Explanation:
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In this case, since pyridinium chloride has a pKb of 8.77 which is a Kb of 1.70x10⁻⁹ and therefore a Ka of 5.89x10⁻⁵ which means it tends to be acidic, we write its ionization via:
Because it is a Bronsted base which donates one hydrogen ion to the water to produce hydronium. Thus, we write the equilibrium expression with the aqueous species only:
![Ka=\frac{[C_5H_5NCl^-][H_3O^+]}{[C_5H_5NHCl]}](https://tex.z-dn.net/?f=Ka%3D%5Cfrac%7B%5BC_5H_5NCl%5E-%5D%5BH_3O%5E%2B%5D%7D%7B%5BC_5H_5NHCl%5D%7D)
In terms of the reaction extent 
, we write:
Thus, solving for we obtain:
Clearly the solution is 0.0048 M because to negative values are not allowed, therefore, since it equals the concentration of hydronium which defines the pH, we write:
![pH=-log([H_3O^+])=-log(0.0048)\\\\pH=2.3](https://tex.z-dn.net/?f=pH%3D-log%28%5BH_3O%5E%2B%5D%29%3D-log%280.0048%29%5C%5C%5C%5CpH%3D2.3)
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Answer: 1 molecule of 
reacts with 1 molecule of 
to give 2 molecules of HCl.
1 mole of reacts with 1 mole of to give 2 moles of HCl.
Explanation:
The given balanced reaction is:
On the particulate level :
1 molecule of reacts with 1 molecule of to give 2 molecules of HCl.
On molar level:
1 mole of reacts with 1 mole of to give 2 moles of HCl.
The net ionic equation of hydrobromic acid would be HBr = H+ + Br-. As we can see, the HBr compound dissociates into ions where one ion is the hydronium ion which characterizes an acid. According to Arrhenius, an acid is a compound which releases hydronium ion in solution.
The type of bonding present in water (H2O) is hydrogen bonding.
In a compund, the proportion must be fixed, unlike mixture. Therefore, if he just combine two elements, there must be excess elements mixed in it.
Second, how did he combined two elements? In order to create a compund, either heat or electricity must be applied.
Therefore, even if he used heat / electricity, he still hasn't got the right proportion, therefore he must have mixed some excess elements into the compund that he thought he made.
