The amount, in grams, of N that the sample will contain will be 2.1 grams.
<h3>Stoichiometric mass ratio</h3>
According to the problem. the mass ratio of H and N in ammonia is 4.7:1.
In other words, every 4.7 grams of H in ammonia must have 1 gram of N.
Now, in a particular ammonia sample, 10 grams of H is present.
The amount of N present can be calculated from the standard mass ratio.
4.1 grams H = 1 gram N
10 grams H = x
4.1x = 1 x 10
x = 10/4.1
x = 2.1 grams
Thus, the mass of nitrogen in the ammonia sample will be 2.1 grams.
More on mass ratios can be found here: brainly.com/question/14577772
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The balanced chemical reaction would be
<span>4Fe(s) + 3O2(g) ---> 2Fe2O3(s)
We are given the amount of Fe to be used in the reaction. We use this as the starting point for the calculations. We do as follows:
25.9 g Fe (1 mol / 55.85 g) ( 2 mol Fe2O3 / 1 mol Fe ) (159.69 g / mol ) = 262.48 g Fe2O3 produced</span>
Answer:
argon is octet because it has eight electrons in its valence shell
Explanation:
Answer is: the % ionization of hypochlorous acid is 0.14.
Balanced chemical
reaction (dissociation) of an aqueous solution of hypochlorous acid:
HClO(aq) ⇄ H⁺(aq) + ClO⁻(aq).
Ka = [H⁺] · [ClO⁻] / [HClO].
[H⁺] is equilibrium concentration of hydrogen cations or protons.
[ClO⁻] is equilibrium concentration of hypochlorite anions.
[HClO]
is equilibrium concentration of hypochlorous acid.
Ka is the acid
dissociation constant.
Ka(HClO) = 3.0·10⁻⁸.
c(HClO) = 0.015 M.
Ka(HClO) = α² · c(HClO).
α = √(3.0·10⁻⁸ ÷ 0.015).
α = 0.0014 · 100% = 0.14%.
