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3 years ago

Legit the last question I need someone help 20 points plus brinlyest

Mathematics

2 answers:

aleksandr82 [10.1K]3 years ago

4 0

The fifth term would be seven

pogonyaev3 years ago

4 0

Answer:

please help me on THIS ONE!!!! brainly.com/question/14080948

Step-by-step explanation:

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Angle C is inscribed in circle O. Line AB is a diameter of circle O. What is the measure of angle B? I can't get the picture but

WINSTONCH [101]

Answer:

Step-by-step explanation:

Since the inscribed angle theorem tells us that any inscribed angle will be exactly half the measure of the central angle that subtends its arc, it follows that all inscribed angles sharing that arc will be half the measure of the same central angle. Therefore, the inscribed angles must all be congruent.

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3 years ago

Math question down below

sergiy2304 [10]

I think the answer is 17.5 years

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3 years ago

A wood board 156 centimeters long is cut into three parts. The two longer parts are the same length and are 15 centimeters longe

Andrei [34K]

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3 years ago

At 106°F, a certain insect chirps at a rate of 67 times per minute, and at 108°F, they chirp 83 times per minute. Write an equat

Step2247 [10]

Answer:

$y=8x-781$

Here, $x$ represents temperature and $y$ denotes rate of chirping per minute.

Step-by-step explanation:

Let $x$ represents temperature and $y$ denotes rate of chirping per minute.

At $106$ °F, a certain insect chirps at a rate of $67$ times per minute.

Take $(x_1,y_1)=(106,67)$

At $108$ °F, they chirp $83$ times per minute.

Take $(x_2,y_2)=(108,83)$

Slope intercept form:

$y-y_1=(\frac{y_2-y_1}{x_2-x_1})(x-x_1)$

$y-67=(\frac{83-67}{108-106})(x-106)\\\\y-67=(\frac{83-67}{108-106})(x-106)\\\\y-67=(\frac{16}{2})(x-106)\\\\y-67=8(x-106)\\y-67=8x-848\\y=8x+67-848\\y=8x-781$

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3 years ago

A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he

mojhsa [17]

Answer:

(A) The minimum sample size required achieve the margin of error of 0.04 is 601.

(B) The minimum sample size required achieve a margin of error of 0.02 is 2401.

Step-by-step explanation:

Let us assume that the percentage of support for the candidate, among voters in her district, is 50%.

(A)

The margin of error, MOE = 0.04.

The formula for margin of error is:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}$

The critical value of z for 95% confidence interval is: $z_{\alpha/2}=1.96$

Compute the minimum sample size required as follows:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.04=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.04}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=600.25\approx 601$

Thus, the minimum sample size required achieve the margin of error of 0.04 is 601.

(B)

The margin of error, MOE = 0.02.

The formula for margin of error is:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}$

The critical value of z for 95% confidence interval is: $z_{\alpha/2}=1.96$

Compute the minimum sample size required as follows:

$MOE=z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}\\0.02=1.96\times \sqrt{\frac{0.50(1-0.50)}{n}}\\(\frac{0.02}{1.96})^{2} =\frac{0.50(1-0.50)}{n}\\n=2401.00\approx 2401$

Thus, the minimum sample size required achieve a margin of error of 0.02 is 2401.

8 0

3 years ago