Radiation
hope that helped!
Explanation:
An object in motion <u>stays</u> <u>at</u> motion An object <u>at</u> <u>rest</u> stays at rest unless acted by an <u>external</u> force.
[ Newton's 1st law of motion ]
Answer:
the ionic radius of the anion ![r^- = 312.52 \ pm](https://tex.z-dn.net/?f=r%5E-%20%3D%20312.52%20%5C%20pm)
Explanation:
From the diagram shown below :
The anion
is located at the corners
The cation
is located at the body center
The Body diagonal length = ![\sqrt{3 \ a }](https://tex.z-dn.net/?f=%5Csqrt%7B3%20%5C%20a%20%7D)
∴ ![2 \ r^+ \ + 2r^- \ = \sqrt{3 \ a} \\ \\ r^+ +r^- = \frac{\sqrt{3}}{2} a](https://tex.z-dn.net/?f=2%20%5C%20r%5E%2B%20%5C%20%2B%202r%5E-%20%5C%20%3D%20%5Csqrt%7B3%20%5C%20a%7D%20%20%5C%5C%20%5C%5C%20r%5E%2B%20%2Br%5E-%20%3D%20%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D%20a)
Given that :
(i.e the ratio of the ionic radius of the cation to the ionic radius of
the anion )
![0.84r^- \ + r^- \ = \frac{\sqrt{3}}{2}a \\ \\ 1.84 r^- = \frac{3}{2}a \\ \\ r^- = \frac{\sqrt{3}}{2*1.84}a](https://tex.z-dn.net/?f=0.84r%5E-%20%5C%20%2B%20r%5E-%20%5C%20%3D%20%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7Da%20%20%5C%5C%20%5C%5C%20%201.84%20r%5E-%20%3D%20%5Cfrac%7B3%7D%7B2%7Da%20%5C%5C%20%5C%5C%20r%5E-%20%3D%20%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%2A1.84%7Da)
Also ; a = 664 pm
Then :
![r^- = \frac{\sqrt{3} }{2*1.84}*664 \ pm\\ \\ r^- = 312.52 \ pm](https://tex.z-dn.net/?f=r%5E-%20%3D%20%5Cfrac%7B%5Csqrt%7B3%7D%20%7D%7B2%2A1.84%7D%2A664%20%5C%20pm%5C%5C%20%5C%5C%20r%5E-%20%3D%20312.52%20%5C%20pm)
Therefore, the ionic radius of the anion ![r^- = 312.52 \ pm](https://tex.z-dn.net/?f=r%5E-%20%3D%20312.52%20%5C%20pm)
the chemical equation will be XY2