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solniwko [45]
3 years ago
11

(BRAINLIEST) Choose 1 from the following Unit 8 sub-topics and expound: (need 5-6 sentences just on ONE of these topics)

Mathematics
1 answer:
Vladimir79 [104]3 years ago
4 0

Answer:n

Step-by-step explanation:

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1. According to this theorem, when a line is a parallel with one of the sides of the triangle and touch or intersect the other two sides of this triangle, then this two sides are divide proportionally by the line.

2. Keeping the information above on mind, you can see that the line CD is parallel to AB and intersect the sides AE And BE, therefore, you con conclude the following:

\frac{AC}{CE}=\frac{BD}{DE}

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The vertices of ΔMNO are M (1, 3), N (4, 9), and O (7, 3). The vertices of ΔPQR are P (3, 0), Q (4, 2), and R (5, 0). Which conc
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Answer:

They are similar by the definition of similarity in terms of a dilation.

Step-by-step explanation:

Given:

The vertices of ΔMNO are M (1, 3), N (4, 9), and O (7, 3). The vertices of ΔPQR are P (3, 0), Q (4, 2), and R (5, 0).

To choose: the correct option

Solution:

According to distance formula distance between points (x_1,y_1),(x_2,y_2) is given by \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

For ΔMNO,

MN=\sqrt{(4-1)^2+(9-3)^2}=\sqrt{(3)^2+(6)^2}=\sqrt{45}\\NO=\sqrt{(7-4)^2+(3-9)^2}=\sqrt{(3)^2+(-6)^2}=\sqrt{45}\\\\MO=\sqrt{(7-1)^2+(3-3)^2}=\sqrt{(6)^2+(0)^2}=\sqrt{36}=6\\

For ΔPQR,

PQ=\sqrt{(4-3)^2+(2-0)^2}=\sqrt{(1)^2+(2)^2}=\sqrt{5}\\QR=\sqrt{(5-4)^2+(0-2)^2}=\sqrt{(1)^2+(-2)^2}=\sqrt{5}\\\\PR=\sqrt{(5-3)^2+(0-0)^2}=\sqrt{(2)^2+(0)^2}=2\\

So,

\frac{MN}{PQ}=\frac{\sqrt{45} }{\sqrt{5} }=\sqrt{9}=3\\ \frac{NO}{QR}=\frac{\sqrt{45} }{\sqrt{5} }=\sqrt{9}=3\\\frac{MO}{PR}=\frac{6 }{2 }=3\\

Therefore, They are similar by the definition of similarity in terms of a dilation.

Two triangles are said to be similar if their sides are proportional.

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