Answer:
X=4
Step-by-step explanation:
It is vertical so it is X=__. It is on x=4 so that is the answer
Answer:
1/6 of one pan of brownies remains
Step-by-step explanation:
2 - 1 and 5/6 equals 1/6
Answer: The m ∡KLM is: 130° .
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Explanation:
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(3x − 4) = (4x − 27) ; (Since these are "bisected, congruent angles", they are equal).
⇒ 3x − 4 = 4x − 27 ;
⇒ Subtract "4x" from EACH SIDE of the equation; and add "4" to EACH SIDE of the equation;
⇒ 3x − 4 − 4x + 4 = 4x − 27 − 4x + 4 ;
to get:
⇒ - 1x = -23 ;
⇒ Divide EACH SIDE of the equation by "-1" ; to isolate "x" on one side of the equation; and to solve for "x" ;
⇒ -1x / -1 = -23 / -1 ; to get:
⇒ x = 23;
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To find m ∡KLM :
m ∡ KLM = (3x − 4) + (4x − 27) ;
{Note: Remember: (3x − 4) = (4x − 27) } ;
So, plug in our solved value for "x" ; which is: "x = 23" into one of the expressions for one of the congruent angles.
Let us start with: "(3x − 4)" .
(3x − 4) = 3x − 4 = 3(23) − 4 = 69 − 4 = 65 .
By plugging in our solve value for "x" ; which is: "x = 23" ; into the expression for the other congruent angle, we should get: "65" ;
Let us try:
(4x − 27) = 4x − 27 = 4(23) − 27 = 92 − 27 = 65. Yes!
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So to find m ∡KLM:
(3x − 4) + (4x − 27) = 65 + 65 = 130° .
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Alternate method:
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At the point which we have:
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To find m ∡KLM :
m ∡ KLM = (3x − 4) + (4x − 27) ; and at which we have our solved value for "x" ; which is: "x = 23" ;
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We can simply plug in our known value for "x" ; which is: "23" ; into the following:
m ∡ KLM = (3x − 4) + (4x − 27) = [(3*23) − 4] + [(4*23) − 27] ;
= (69 − 4) + (92 − 7) = 65 + 65 = 130° .
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{Note: Using this method, we determine that each angle is equal; that is, "65° ".}.
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Answer:
Explicit: -2*2^(n-1)
Recursive: 2*aₙ₋₁
Step-by-step explanation:
To write a explicit formula for this geometric sequence you follow the following formula/template
Firstnumber*commonratio^(n-1)
Seeing that the common ratio is 2 we can start plugging numbers in and get
-2*2^(n-1)
For a recursive formula we follow the following template
common ratio * the n-1 term
So we could write this as
2*aₙ₋₁
<h3>Answer:</h3>
It depends:
- 4 if she starts at 4
- 5 if she starts at 0
<h3>Explanation:</h3>
Louise needs to end up a total of 5 times 4 away from zero.
If she starts at 4, which is 1 times 4, then she needs to jump 4 more times, to 2, 3, 4, 5 times 4.
If she starts at 0, then she needs to jump 5 times to 1, 2, 3, 4, 5 times 4. (The values at the end of each jump will be {4, 8, 12, 16, 20}.)