Question

an alloy contains 56g of pure silver and 22g of pure copper what is the percentage(%) of silver in the alloy?

Answer 1

To get the ans divide 5600by 78 and there is ur answer

Answer 2

Answer: The percentage of silver in the alloy is 71.8 %.

Explanation:

To calculate the percentage composition of a substance in a mixture, we use the equation:

$\%\text{ composition of substance}=\frac{\text{Mass of substance}}{\text{Mass of mixture}}\times 100$

We are given:

Mass of pure silver = 56 g

Mass of pure copper = 22 g

Mass of alloy = 56 + 22 = 78 g

Putting values in above equation:

$\%\text{ composition of silver}=\frac{56}{78}\times 100=71.8\%$

Hence, the percentage of silver in the alloy is 71.8 %.