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balandron [24]
3 years ago
9

100 point question!! A driver begins to brake when her car is traveling at 15.0 m/s, and the car comes to a stop 4.0 s later. Ho

w much farther does the car go after the driver begins to brake, assuming constant acceleration?
Physics
1 answer:
Anni [7]3 years ago
3 0

Answer:

30 m

Explanation:

Let's list out the known variables that we are given in this question.

  • v₀ = 15 m/s
  • v = 0 m/s
  • t = 4 s

We are trying to solve for displacement in the x-direction.

  • Δx = ?

Find which constant acceleration equation contains all 4 of these variables.

  • \displaystyle \triangle x = \Big (\frac{v+v_0}{2} \Big ) t

Plug the known values into the equation and solve for delta x.

  • \displaystyle \triangle x = \Big (\frac{0+15}{2} \Big ) \cdot 4
  • \displaystyle \triangle x = \Big (\frac{15}{2} \Big ) \cdot 4  
  • \displaystyle \triangle x =\frac{60}{2}
  • \triangle x = 30

The car goes 30 m after the driver begins to brake.

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An object 82 cm high forms a virtual image 4.1 cm high located 4.6 cm behind a mirror. Find the object distance.
ioda

Answer:

The object distance is 92 cm.  

Explanation:

let v be the image distance and h be the height of the image, let u the be the object distance and H be the height of the object.

then, the magification of the mirror is given by:

m = -v/u and m = h/H

so, -v/u = h/H

         u = -v×H/h

            = -(-4.6)×(82)/(4.1)

            = 92 cm

Therefore, the object distance is 92 cm.

8 0
3 years ago
Please guys i need help in this
JulijaS [17]

Answer:

10 seconds

Explanation:

We have the equation V = at  (speed = acceleration x time)

We want to find the time, so can rearrange to T = V/a (time = speed / acceleration).

From the question, we know V is 5 and a is 0.5.

Now we can substitute that into our equation: 5/0.5 = 10.

So the time is 10 seconds.

Hope this helps! Let me know if you have any questions :)

8 0
3 years ago
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Amanda [17]

Solution :

A) Electric current is the flow of electrons .

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3 0
3 years ago
How do foraminifera found in rock layers above the k-t boundary compare to those in rock layers below?
creativ13 [48]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

Below are the choices that can be found elsewhere:

Foraminifera above the boundary are larger and more diverse than those below.
Foraminifera above the boundary are larger and less diverse than those below.
Foraminifera above the boundary are smaller and more diverse than those below.
<span>Foraminifera above the boundary are smaller and less diverse than those below

The answer is </span>Foraminifera above the boundary are smaller and less diverse than those below
<span>

</span>
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schepotkina [342]

Answer:

Physical properties are those which can be measured or observed without changing the substance.

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<u><em>Hope that helps</em></u>

7 0
4 years ago
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