This question is incomplete, the complete question is;
A weightlifter holds a 1,300 N barbell 1 meter above the ground. One end of a 2-meter-long chain hangs from the center of the barbell. The chain has a total weight of 400 N. How much work (in J) is required to lift the barbell to a height of 2 m?
What is the average force (average with respect to height of the barbell from the ground) exerted by the weightlifter in the process?
Answer: Average force exerted by the weightlifter in the process = 1600N
Explanation:
To find Work done to lift a barbell and half of the hanging chain we say;
W₁ = ( 1300N + (1/2 × 400N)) × 1m
W₁ = (1300 + 200) Nm
W₁ = 1500J
now work done to lift the upper half of the chain we say:
W₂ = (1/2 × 400N) × (1/2 × 1m)
W₂ = 200N × 0.5m
W₂ = 100J
So total work done will be
W = W₁ + W₂
W = 1500J + 100J
W = 1600J
To find the average force exerted by the weight lifter, we say;
F = W/D
F = (1600 / 1m) N
F = 1600N
∴Average force = 1600N
Force = mass * acceleration
F = ma
8 N = 2 kg * a
8 = 2a
2a = 8
a = 8/2 = 4
acceleration = 4 m/s²
Answer:
Andre is really disappointed that he didn't make the basketball team as a player this year, but he decides to accept the coach's offer to assist the team in other ways in doing so, he is exercising the self-care strategy of?
Answer
A
Answer:
a
Explanation:
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The "unstretched length" is shorter than the actual unloaded length because the load applied to the material caused the extension of the material thereby increasing its length.
<h3>Hooke's law</h3>
Hooke's law states that the force applied to an elastic material is directly proportional to the extension of the elastic material.
F = kx
where;
- F is the applied force
- k is the spring constant
- x is the extension
Thus, we can conclude that, the "unstretched length" is shorter than the actual unloaded length because the load applied to the material caused extension of the material thereby increasing the length of the material.
Learn more about Hooke's law here: brainly.com/question/2648431