Answer:
19 cm³
Explanation:
The coefficient of thermal expansion is the ratio of the change in volume to the reference volume for each degree change in temperature. Hence the change in volume is found by multiplying by the reference volume and the change in temperature.
(1000 cm³)(0.950·10⁻³/K)(50-30)K = 19 cm³ . . . volume increase
Answer:
P = 52 kPa
Explanation:
Hidrostatic pressure is defined as the product of the height of liquid (h) by its specific weight (ρ) and by the acceleration of gravity (g).
In the first scenario, the atmospheric pressure is:
In the second scenario, h = 4.2 + 1 m. Therefore, the pressure at the bottom of the barrel is:
The pressure on the bottom when water is added to fill the pipe to its top is 52 kPa.
In this question, we know that mass= 10 kg = 10 x 1000 = 10,000 g
Distance = 1 m and Time = 0.5 s
Power = Force x Velocity
Velocity = Distance / Time = 1 m / 0.5 s = 2 m/s
So, Power = Force x (Distance / Time)
But Force= Mass x Acceleration due to gravity (g)
So, Force = 10 kg x 9.8 m/s
= 98
Therefore, Power =Force x Velocity= 98 x 2 =
196 W
'H' = height at any time
'T' = time after both actions
'G' = acceleration of gravity
'S' = speed at the beginning of time
Let's call 'up' the positive direction.
Let's assume that the tossed stone is tossed from the ground, not from the tower.
For the stone dropped from the 50m tower:
H = +50 - (1/2) G T²
For the stone tossed upward from the ground:
H = +20T - (1/2) G T²
When the stones' paths cross, their <em>H</em>eights are equal.
50 - (1/2) G T² = 20T - (1/2) G T²
Wow ! Look at that ! Add (1/2) G T² to each side of that equation,
and all we have left is:
50 = 20T Isn't that incredible ? ! ?
Divide each side by 20 :
<u>2.5 = T</u>
The stones meet in the air 2.5 seconds after the drop/toss.
I want to see something:
What is their height, and what is the tossed stone doing, when they meet ?
Their height is +50 - (1/2) G T² = 19.375 meters
The speed of the tossed stone is +20 - (1/2) G T = +7.75 m/s ... still moving up.
I wanted to see whether the tossed stone had reached the peak of the toss,
and was falling when the dropped stone overtook it. The answer is no ... the
dropped stone was still moving up at 7.75 m/s when it met the dropped one.