That would be 0 degrees Celsius aka the melting point of water.... If you look at the diagram I attached you notice that at 0 degrees Celsius it is flat, this is because much heat is needed at this point for water to rise to 1 degree... It is the same for the boiling point (100)
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Answer:
(a) t = 0 s
(b) t = 0 s, 30 s, 55 s
(c) t = 40 s to t = 60 s
(d) t = 10 s to t = 15 s
(e) a = 6 m/s^2
Explanation:
(a) The car is at starting position at t = 0 s and v = 0 m/s.
(b) The velocity of car is zero when the time is t = 0 s, 30 s and 55 s.
(c) from t = 40 s to 60 s the car is moving in the negative direction.
(d) The fastest speed is 60m/s from t = 10 s to t = 15 s.
(e) The slope of the velocity time graph gives acceleration.
a = (60 - 0) / (10 - 0) = 6 m/s^2
Answer:
The electric field intensity is <u>30000 N/C.</u>
Explanation:
Given:
Magnitude of the point charge is, 
Distance of the given point from the point charge is, 
Electric field intensity is directly proportional to the magnitude of point charge and inversely proportional to the square of the distance of the point and the given charge.
Therefore, electric field intensity 'E' at a distance of 'd' from a point charge 'q' is given as:

Plug in
. Solve for 'E'.

Therefore, the electric field intensity at a point 3 cm from the point charge is 30000 N/C.
Answer:
206 m
Explanation:
The energy output of the scooter battery = 135 Wh = 135 W × 3600 s = 486000 J.
If 60.0% accounts for losses, then
useful energy = (100 - 60)% of 486000 J = 40% × 486000 J = 194400 J
The energy needed to move through an altitude = product of weight and altitude


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The change in Gravitational Potential Energy (GPE) is actually 0! Think about it:
What is the formula for it?
Well, GPE = mgh.
So, when the height is the same in both cases, we know the gravitational potential energy is the same. Therefore, change in GPE = 0.
Sure, GPE did transform to KE during the swing, but all of that KE transformed back into the original amount of GPE.
Hope this helped! Please press “Thanks!”