The formula for the half life is simply:
t1/2 = ln 2 / k
where k is the rate constant and can be calculated from
the formula:
rate = k [A]
where [A] is the initial concn = 0.25 M
k = 4.36 × 10-2 M s-1 / 0.25 M = 0.1744 s-1
t1/2 = ln 2 / 0.1744 s-1
<span>t1/2 = 3.97 s</span>
When using a graph, you plot data on on a grid with an x-axis and a y-axis.
Answer: graph
When a sample of a gas is heated in a sealed, rigid
container from 200 degree Kelvin to 400 degree Kelvin, the pressure exerted by
the gas is increased by a factor 2. Heating any gas actually increases the
volume of the gas within a container. As the temperature of the gas rises, the
molecules of the gas start moving faster and start striking the walls of the
container in which it is kept with more force. The volume of the container
tries to expand to accommodate the fast colliding molecules of the gas.
Answer:
25%
Explanation:
Half life means that 50% of the sample is gone at 3.3 years. This means that an additional 3.3 years (total 6.6 years) will reduce the sample a further 50% from the point at 3.3 years. In numbers, this means 50% of 50% (0.50*0.50), which is 25%.
Answer:
<h2>mass = 19.98 g</h2>
Explanation:
To find the mass of 1.11 mol of H2O we must first find it's molecular mass after that we use the formula
<h3>m = M × n</h3>
where
m is the mass
M is the molecular mass
n is the number of moles
From the question
n = 1.11 mol
Taking
M( H) = 1 g/mol , M(O) = 16 g/mol
We have
M( H2O) = 2 + 16 = 18 g/mol
So we have
m = 1.11 × 18
We have the final answer as
<h3>mass = 19.98 g</h3>
Hope this helps you