Answer:
The question to your answer is: mass = 12 kg
Explanation:
Data
Force = 12 N
acceleration = 6 m/s²
mass = ?
Formula
Force = mass x acceleration (Newton's second law of motion)
mass = Force / acceleration
Substitution
mass = 12 N / 6 m/s²
mass = 12 kg result
Answer:
The acceleration of the centre of mass of spool A is equal to the magnitude of the acceleration of the centre of mass of spool B.
Explanation:
From the image attached, the description from the complete question shows that the two spools are of equal masses (same weight due to same acceleration due to gravity), have the same inextensible wire with negligible mass is attached to both of them over a frictionless pulley; meaning that the tension in the wire is the same on both ends.
And for the acceleration of both spools, we mention the net force.
The net force acting on a body accelerates the body in the same direction as that in which the resultant is applied.
For this system, the net force on either spool is exactly the same in magnitude because the net force is a difference between the only two forces acting on the spools; the tension in the wire and their similar respective weights.
With the net force and mass, for each spool equal, from
ΣF = ma, we get that a = ΣF/m
Meaning that the acceleration of the identical spools is equal also.
Hope this Helps!
Answer:
The frequency of the simple harmonic motion of a 67.6 kg diver on the board = 2.48 Hz
Explanation:
The frequency in simple harmonic motion is related to spring constant and mass causing the motion through the relation
f = (1/2π) √(k/m)
When mass = 10 kg, f = 6.90 Hz,
6.9 = (1/2π) √(k/10)
(√(k/10) = 6.9×2π = 43.354
k/10 = 43.354² = 1879.57
K = 18795.7 N/m
When a diver of mass 67 kg climbs the diving board, the total mass on the diving board now becomes (10+67.6) = 77.6 kg
Spring constant of the diving board doesn't change,
So, the frequency is then given by
f = (1/2π) √(18795.7/77.6)
f = 2.48 Hz
Answer:
The fundamental frequency of the stretched string is:
[ T = Tension and μ = mass per unit length]
Here,
μ = 
If T is halved and A is doubled,
Thus, the frequency is reduced to half if its tension is halved and the area of cross-section of the string is doubled.
In order to cause electrons to be ejected from the surface of this metal you should use light of a shorter wavelength.
The photoelectric effect is the emission of electrons when electromagnetic radiation, such as light, hits a material. Electrons emitted in this manner are called photoelectrons. The phenomenon is studied in condensed matter physics, and solid state and quantum chemistry to draw inferences about the properties of atoms, molecules and solids. The effect has found use in electronic devices specialized for light detection and precisely timed electron emission.
This process is also often referred to as photoemission. In terms of their behaviour and their properties, photoelectrons are no different from other electrons. The prefix, photo-, simply tells us that the electrons have been ejected from a metal surface by incident light.
The photons of a light beam have a characteristic energy, called photon energy, which is proportional to the frequency of the light. In the photoemission process, when an electron within some material absorbs the energy of a photon and acquires more energy than its binding energy, it is likely to be ejected. If the photon energy is too low, the electron is unable to escape the material. Since an increase in the intensity of low-frequency light will only increase the number of low-energy photons, this change in intensity will not create any single photon with enough energy to dislodge an electron. Moreover, the energy of the emitted electrons will not depend on the intensity of the incoming light of a given frequency, but only on the energy of the individual photons.
Learn more about Photoelectric effect here : brainly.com/question/1408276
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