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Nimfa-mama [501]
3 years ago
15

A solenoid with 500 turns has a radius of 0.040 m and is 40 cm long. if this solenoid carries a current of 12 a, what is the mag

nitude of the magnetic field near the center of the solenoid? (? 0 = 4? × 10-7 t · m/a
Physics
1 answer:
frosja888 [35]3 years ago
7 0
Are there any options? I had one similar to this not to long ago

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Find the ratio of the diameter of iron to copper wire, if they have the same resistance per unit length (as they might in househ
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Answer:

The ratio of the diameter of iron to Cu is;

\frac{d{Fe}   }{ d{Cu}   } =\sqrt{\frac{p_{Fe} }{ p_{Cu} }}

Explanation:

R=(ρL)/A

  • R is resistance,
  • L is length,
  • A is area,
  • ρ is resistivity
  • d is diameter

from the question the two materials have the same resistance per unit length.

\frac{R}{L}= \frac{p}{A}

\frac{R}{L}   for iron = \frac{R}{L}  for copper

This means we can equate ρ/A for both materials.

\frac{p_{Fe} }{A_{Fe} } =\frac{p_{Cu} }{A_{Cu} }

re-arranging the equation we have,

\frac{A_{Fe}}{A_{Cu} } =\frac{p_{Fe} }{ p_{Cu} }

A=\pi \frac{d^{2} }{4}

\frac{A_{Fe}}{A_{Cu} } =\frac{d^{2}{Fe}   }{ d^{2}{Cu}   }

\frac{d^{2}{Fe}   }{ d^{2}{Cu}   } =\frac{p_{Fe} }{ p_{Cu} }

\frac{d{Fe}   }{ d{Cu}   } =\sqrt{\frac{p_{Fe} }{ p_{Cu} }}

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