The percent of the water that evaporated is 5/9 converted to a percent.
Potassium ion (K+) ; 18 e- = [Ar]
Highest noble Gas is [Ar] at 18 e-
Neutral K is 19 e- with shorthand: [Ar] 4s1
eliminating an electron, eliminates 4s1 and makes it same configuration as Argon.
Answer:- 1.35 grams of NaF must be added.
Solution:- HF is a weak acid. So, if NaF is added to it then a buffer solution will be formed and the Handerson equation is used for buffer solutions to find out the pH. Since the pH is given, so we could easily calculate the moles and then grams of NaF required to achieve the mentioned pH.
Handerson equation is:
Moles of HF could be calculated from it's given volume and molarity as:
= 0.025 mol HF
pKa is calculated from given Ka value using the formula:
pKa = 3.14
Let's plug in the values in the Handerson equation:
On taking antilog:
base = 0.03225 mol
Molar mass of NaF is 41.99 grams per mol. Let's multiply the moles by molar mass to get the grams of NaF.
= 1.35 g
So, 1.35 grams of NaF must be added to 50.0 mL of 0.500 M HF solution to achieve a pH of 3.25.
The gas 0.735/0.523=1.405moles.
so 1.405 times of gas is present than what was at the start. 0.523moles of argon took up 0.723L(723mL) so 1.405 times as much gas would take 1.405 times as much space. so the volume would be ,
1.405*0.723=1.015L